二分制--找最小值去重

找最小值的算法

去重的算法

<script>
var arr = [1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 5, 5, 6, 7, 8, 9, 0, 0, 3, 4, 5];

function findInArr(arr,n){
for(var i = 0; i < arr.length; i++){
if(arr[i] == n)return true;
}
return false;
}

function removeDup(arr, s, e){

if(s > e){
return false;
}else if(s == e){
return [arr[s]];
}

var c = Math.floor((s + e) / 2);
var l = removeDup(arr, s, c);
var r = removeDup(arr, c + 1, e);

for(var i = 0; i < r.length; i++){
if(!findInArr(l,r[i])){
l.push(r[i]);
}
}
return l;
}

console.log(removeDup(arr, 0, arr.length - 1));
</script>

原文地址:https://www.cnblogs.com/w-xiaojia/p/7130234.html