UVA4731:Cellular Network

根据排序不等式可知,逆序和最小(就是两个向量坐标一个递增一个递减,那么乘起来就最小)

所以排一下序,然后做一下线性dp即可

#include<cstdio>
#include<cstdlib>
#include<algorithm>
#include<cstring>
#define MAXN 105
#define ll long long
using namespace std;
double f[MAXN][MAXN];
int n,m;
double c[MAXN];
double s[MAXN];
int a[MAXN];
int sum;
bool comp(const int &p1,const int &p2){
    return (p1>p2);    
}
void solve(){
    scanf("%d%d",&n,&m);
    sum=0;
    for(int i=1;i<=n;i++){
        scanf("%d",&a[i]);
        sum+=a[i];
    }
    sort(a+1,a+n+1,comp);
    for(int i=1;i<=n;i++){
        c[i]=1.0*a[i]/sum;
        s[i]=s[i-1]+c[i];
    }
    for(int i=1;i<=n;i++){
        f[i][1]=i*s[i];
        for(int j=2;j<=m;j++){
            f[i][j]=100000000000;
            for(int k=j-1;k<i;k++){
                f[i][j]=min(f[i][j],f[k][j-1]+(s[i]-s[k])*i);
            }
        }
    }
    printf("%.4f
",f[n][m]);
}
int main()
{
//    freopen("data.in","r",stdin);
    int T;
    scanf("%d",&T);
    while(T--){
        solve();
    }
    return 0;
}
原文地址:https://www.cnblogs.com/w-h-h/p/7854544.html