[LeetCode] Linked List Cycle

Given a linked list, determine if it has a cycle in it.

Follow up:
Can you solve it without using extra space?

思路:快慢指针的应用。快慢指针指的是移动的步长,即每次向前移动的快慢。例如可以让快指针每次沿链表向前移动2,慢指针每次向前移动1次。

   如果快指针到达NULL,说明链表以NULL为结尾,没有环。如果快指针追上慢指针,则表示有环。

   时间复杂度O(n),空间复杂度O(1)

 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 class Solution {
10 public:
11     bool hasCycle(ListNode *head) {
12         if (head == NULL) return head;
13         
14         ListNode *slow = head, *fast = head;
15         while (fast != NULL && fast->next != NULL) {
16             fast = fast->next->next;
17             slow = slow->next;
18             if (fast == slow) return true;
19         }
20         
21         return false;
22     }
23 };
原文地址:https://www.cnblogs.com/vincently/p/4072091.html