hdu 1059 Dividing 多重背包

就是看能不能装满给定容量的背包。

#include <stdio.h>
#include <string.h>
int dp[200000],a[15];
int main()
{
    int cas=0,c;
    int i,j,k;
    while(1)
    {
        int sum=0;
        cas++;
        for(i=1;i<=6;i++)
        {
            scanf("%d",&a[i]);
            sum+=a[i]*i;
        }
        if(sum==0) break;
        printf("Collection #%d:
",cas);
        if(sum%2!=0)
        {
            printf("Can't be divided.

");
            continue;
        }
        sum/=2;
        memset(dp,0,sizeof(dp));
        dp[0]=1;
        for(i=1;i<=6;i++)
        {
            if(a[i]==0) continue;
            for(j=1;j<=a[i];j*=2)
            {
                c=j*i;
                for(k=sum;k>=c;k--)
                    if(dp[k-c])
                        dp[k]=1;
                a[i]-=j;
            }
            c=a[i]*i;
            if(c!=0)
            {
                 for(k=sum;k>=c;k--)
                    if(dp[k-c]) dp[k]=1;
            }
        }
        if(dp[sum]) printf("Can be divided.

");
        else printf("Can't be divided.

");
    }
    return 0;
}
原文地址:https://www.cnblogs.com/vermouth/p/3839936.html