Codeforces Round #261 (Div. 2)

构造

看成k进制的d位数。。

 1 n,k,d = map(int, raw_input().split())
 2 if n > k**d: print -1
 3 else:
 4     ans = []
 5     for i in range(n):
 6         tmp = i
 7         cur = []
 8         for j in range(d):
 9             cur.append(tmp%k+1)
10             tmp /= k
11         ans.append(cur)
12     for i in range(d):
13         for j in ans:
14             print j[i],
15         print ''

View Code

D.http://codeforces.com/contest/459/problem/D

树状数组求逆序数

没怎么看懂思路。。噗。。

参考：http://www.cnblogs.com/yuiffy/p/3916512.html

E.http://codeforces.com/contest/459/problem/E

 1 /*Author :usedrose  */
 2 /*Created Time :2015/8/9 21:56:08*/
 3 /*File Name :2.cpp*/
 4 #pragma comment(linker, "/STACK:1024000000,1024000000") 
 5 #include <cstdio>
 6 #include <iostream>
 7 #include <algorithm>
 8 #include <sstream>
 9 #include <cstdlib>
10 #include <cstring>
11 #include <climits>
12 #include <vector>
13 #include <string>
14 #include <ctime>
15 #include <cmath>
16 #include <deque>
17 #include <queue>
18 #include <stack>
19 #include <set>
20 #include <map>
21 #define INF 0x3f3f3f3f
22 #define eps 1e-8
23 #define pi acos(-1.0)
24 #define MAXN 1110
25 #define MAXM 300110
26 #define OK cout << "ok" << endl;
27 #define o(a) cout << #a << " = " << a << endl
28 #define o1(a,b) cout << #a << " = " << a << "  " << #b << " = " << b << endl
29 using namespace std;
30 typedef long long LL;
31 
32 struct node {
33     int u, v, w;
34     bool operator<(const node& ss) const {
35         return w < ss.w;
36     }
37 }e[MAXM];
38 int n, m;
39 int dp[MAXM], g[MAXM];
40 
41 int main()
42 {
43     cin.tie(0);
44     ios::sync_with_stdio(false);
45     cin >> n >> m;
46     for (int i = 0;i < m; ++ i) 
47         cin >> e[i].u >> e[i].v >> e[i].w;
48     sort(e, e + m);
49     int t = 0, ans = 0;
50     for (int i = 0;i < m; ++ i) {
51         dp[i] = g[e[i].u] + 1;
52         if (e[i].w != e[i+1].w) {
53             for (int j = t; j <= i; ++ j)
54                 g[e[j].v] = max(dp[j], g[e[j].v]);
55             t = i+1;
56         }
57         ans = max(ans, dp[i]);
58     }
59     cout << ans << endl;
60     return 0;
61 }

View Code

参考

http://blog.csdn.net/y990041769/article/details/38709519