程序只运行一次的方法

方法一:使用Mutex来进行

1. 首先要添加如下的namespace:

using System.Threading;

2. 修改系统Main函数,大致如下:

        bool bCreatedNew;

       

        //Create a new mutex using specific mutex name

        Mutex m =new Mutex( false, "myUniqueName", out bCreatedNew );

        if( bCreatedNew )

            Application.Run(new yourFormName());

如上面编码就可以了,要注意的一点是,在给Mutex起名字的时候,不要太简单,以防止和其他程序的Mutex重复,从而达不到所预想的效果。

方法二:使用Process来进行

1. 首先要添加如下的namespace:

using System.Diagnostics;

using System.Reflection;

2. 添加如下函数:

        public static Process RunningInstance()

        {

            Process current = Process.GetCurrentProcess();

            Process[] processes = Process.GetProcessesByName(current.ProcessName);

            //Loop through the running processes in with the same name

            foreach (Process process in processes)

            {

                //Ignore the current process

                if (process.Id != current.Id)

                {

                    //Make sure that the process is running from the exe file.

                    if (Assembly.GetExecutingAssembly().Location.Replace("/", "\\") == current.MainModule.FileName)

                    {

                        //Return the other process instance.

                        return process;

                    }

                }

            }

            //No other instance was found, return null.

            return null;

        }

3. 修改系统Main函数,大致如下:

            if( RunningInstance() == null )

                Application.Run(new yourFormName());

如上面编码就可以了,要注意的一点是,在判断进程模块文件名是否相等这部分的代码,是可选的。如果当前的程序在文件系统中只存在一个的话,以上的方法是可以的;否则不要删除这部分的代码。

原文地址:https://www.cnblogs.com/tuyile006/p/1217330.html