- 有几点需要注意的地方一是将right转化为与left在在同一节
while (left + 4 <= right)
{
right -= 4;//每次将right移动4位,直到left与right在同一节
}
参考代码:
#define _CRT_SECURE_NO_WARNINGS
#include<cstdio>
#include<cstring>
#include<cstdlib>
char num[10][5] = { "ling","yi","er","san","si","wu","liu","qi","ba","jiu" };
char wei[5][5] = { "Shi","Bai","Qian","Wan","Yi" };
int main()
{
char str[15];
scanf("%s", str);//按字符串输入数字
int len = strlen(str);
int left = 0, right = len - 1;//分别指向字符串的首尾元素
if (str[0] == '-')
{
printf("Fu");
left++;
}
while (left + 4 <= right)
{
right -= 4;//每次将right移动4位,直到left与right在同一节
}
while (left < len)
{
bool flag = false;//flag==false表示没有累计的0
while (left <= right)
{
if (left > 0 && str[left] == '0')
{
flag = true;
}
else
{
if (flag == true)
{
printf(" ling");
flag = false;
}
if (left > 0) printf(" ");//只要不是首位都要在每个后面输出空格
printf("%s", num[str[left] - '0']);//输出当前位数字
if (left != right)
{
printf(" %s", wei[right - left - 1]);
}
}
left++;
}
if (right != len - 1)
{
printf(" %s", wei[(len - 1 - right) / 4 + 2]);
}
right += 4;
}
system("pause");
return 0;
}