HDU-2602 Bone Collector

简单01背包

状态转移方程 dp[j] = max{dp[j], dp[j - volume[i]] + value[i]};

 1 #include<iostream>
 2 #include<algorithm>
 3 #include<cstring>
 4 #define mem(a) memset(a, 0, sizeof(a))
 5 using namespace std;
 6 const int maxn = 1050;
 7 int dp[maxn];
 8 int value[maxn]; int volume[maxn];
 9 int main()
10 {
11     int T; cin >> T;
12     while(T--) {
13         int n, v;
14         cin >> n >> v;
15         for(int i = 1 ; i <= n ; i++) cin >> value[i];
16         for(int i = 1 ; i <= n ; i++) cin >> volume[i];
17         mem(dp);
18         for(int i = 1 ; i <= n ; i++)
19             for(int j = v ; j >= volume[i] ; j--)
20                 dp[j] = max(dp[j - 1], dp[j - volume[i]] + value[i]);
21         cout << dp[v] << endl;
22     }
23     return 0;
24 }
原文地址:https://www.cnblogs.com/tooyoungtoosimple/p/4470592.html