Java for LeetCode 201 Bitwise AND of Numbers Range

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.

For example, given the range [5, 7], you should return 4.

解题思路:

本题有很多思路,最简单的方法:

result就是m和n二进制前面相同的部分!!!

JAVA实现如下:

    public int rangeBitwiseAnd(int m, int n) {
    	int count=0;
    	while(m!=n){
    		n>>>=1;
    		m>>>=1;
    		count++;
    	}
        return m<<count;
    }
原文地址:https://www.cnblogs.com/tonyluis/p/4558866.html