790. 数的三次方根

#include<iostream>
#include<cstdio>

using namespace std;

int main(){
    double n;
    
    cin >> n;
    
    double l = -10000, r = 10000;
    
    while(r - l > 1e-8){ // 由于要保留6位小数,那么写成1e-8,而且要用double,用float超时
        double mid = (l + r) / 2;
        if(mid * mid * mid >= n) r = mid;
        else l = mid;
    }
    
    printf("%.6lf", l);
}
原文地址:https://www.cnblogs.com/tomori/p/13469197.html