七牛文件上传-python

 1 #!/usr/bin/env python
 2 # -*- coding: utf-8 -*-
 3 
 4 import sys
 5 import os
 6 
 7 from sevencow import CowException
 8 from sevencow import Cow
 9 
10 
11 
12 ACCESS_KEY = 'YOUR_ACCESS_KEY'
13 SECRET_KEY = 'YOUR_SECRET_KEY'
14 BUCKET_NAME = 'YOUR_BUCKET_NAME'
15 
16 cow = Cow(ACCESS_KEY, SECRET_KEY)
17 b = cow.get_bucket(BUCKET_NAME)
18 
19 
20 if __name__ == '__main__':
21     #获得输入
22     file_path = sys.argv[1]
23     #判断路径是否存在,是否是文件
24     if os.path.exists(file_path) and os.path.isfile(file_path):
25         try:
26             b.put(file_path)
27         except CowException as e:
28             print e.url,e.status_code,e.reason,e.content

看代码就知道,需要先安装sevencow,上传文件很简单,以文件路径为参数即可。

原文地址:https://www.cnblogs.com/tk091/p/3819353.html