ParseUrl

#!/usr/bin/python
# coding:utf-8

import re
import urlparse

# 解析url
def ParseUrl(url):
    if not re.search(r"^http[s]?://",url):
        if ":443" in url:
            url = "https://" + url
        else:
            url = "http://" + url
        return url
原文地址:https://www.cnblogs.com/tk091/p/3693060.html