As the error message states, the case expressions must be constant. The compiler builds this as a very fast look-up table at compile time and it can't do that if there is a possibility that the values could change as the program runs.
If you do need them to be variable, not constant, your best bet is to use if/else statements instead.
方法一：
The case statements require integral value which must be known at compile-time, which is what is meant by constant here. But the const members of a class are not really constant in that sense. They're are simply read-only.
Instead of fields, you can use enum :
class ThisClass
{
public:
enum Constants
{
EXAMPLE_CONSTANT = 10,
ANOTHER_CONSTANT = 20
};
};And then you can write,
switch(c)
{
case ThisClass::EXAMPLE_CONSTANT:
//code
break;
case ThisClass::ANOTHER_CONSTANT:
//code
break;
};I am getting a 'case expression not constant' error in a switch statement. However, the header provides a definition for the used constants, and the constructor provides initialisation for them in its initialization list.
Additionally, when I mouse over the "problem" statements it identifies them as constants.
const int ThisClass::EXAMPLE_CONSTANT
error expression must have a constant valueThis seems a little counter-intuitive to me. I did some research and found a similar problem that someone else had. They were told that all constants must in fact be initialised in 'main' and that this was a limitation of the language. Is this really the case? It seems unlikely.
You need a "real" compile time integer constant. const in C++ means read-only, and a const variable can be initialized just like int y = 0; const int x = y;, making x a read-only copy of the value y had at the time of initialization.
With a modern compiler, you can either use enums or constexprs to store (integral) members of compile-time-constness:
class Foo {
public:
static constexpr int x = 0;
enum { y = 1 };
};
int main () {
switch (0) {
case Foo::x: ;
case Foo::y: ;
}
}