sql计算两个时间之间的差,并用时分秒表示


这是自己写的方法,总觉得会有更好的办法实现这个效果呢?

SELECT 
case when CONVERT(nvarchar,DATEDIFF(SECOND,FinishAt,getdate() ))>86400  then
CONVERT(nvarchar, DATEDIFF(SECOND,FinishAt,getdate() )/86400)+''+CONVERT(nvarchar, DATEDIFF(SECOND,FinishAt,getdate() )%86400/3600)+''+CONVERT(nvarchar, DATEDIFF(SECOND,FinishAt,getdate() )%86400%3600/60)+''+CONVERT(nvarchar, DATEDIFF(SECOND,FinishAt,getdate() )%86400%3600%60)+''
when CONVERT(nvarchar,DATEDIFF(SECOND,FinishAt,getdate() ))>3600 then 
CONVERT(nvarchar, DATEDIFF(SECOND,FinishAt,getdate() )/3600)+''+CONVERT(nvarchar, DATEDIFF(SECOND,FinishAt,getdate() )%3600/60)+''+CONVERT(nvarchar, DATEDIFF(SECOND,FinishAt,getdate() )%3600%60)+''
when  CONVERT(nvarchar,DATEDIFF(SECOND,FinishAt,getdate() ))>60 then
CONVERT(nvarchar, DATEDIFF(SECOND,FinishAt,getdate() )/60)+''+CONVERT(nvarchar, DATEDIFF(SECOND,FinishAt,getdate() )%60)+''
else CONVERT(nvarchar,DATEDIFF(SECOND,FinishAt,getdate() ))+'' end TimeSpend   
  FROM [BPMDB].[dbo].[BPMInstTasks] A
原文地址:https://www.cnblogs.com/tianxiaotian/p/10277141.html