from collections import Counter
a=['bj', 'bj', 'bj', 'gz', 'shh', 'shh']
d=Counter(a)
print d
print d.most_common()
print d.most_common()[0]
print d.most_common()[0][0]
方法二：
一个网友的写法：
def sortbylistcount(self,list):
cnt=0
city=""
for x in list:
if list.count(x)>cnt:
city=x
cnt=list.count(x)
return city
方法三：
for n in a:
old=a.count(n)
num=max(a.count(m) for m in a)
if num==old:
print n
break