leetcode ip地址组合

class Solution {
public:
vector<int>v1;
vector<string>v;
int count;
    string inttostring(int n)
    {
        stringstream ss;
        string str;
        ss<<n;
        ss>>str;
        return str;
    }
    vector<string> restoreIpAddresses(string s) 
    {      
       v.clear();
       if(s.size()>12)return v;
       v1.clear();
       count=0;
       ipdivide(0,s);
       return v;
    }
    void ipdivide(int depth,string s)
    {
        if(depth==s.size()&&count==4)
        {
            string ipaddress="";
            for(int i=0;i<4;i++)
            {
                ipaddress+=inttostring(v1[i]);
                if(i!=3)ipaddress+=".";
            }
            v.push_back(ipaddress);             
        }
        if(depth<s.size())
        {
            int temp=0;
            for(int i=depth;i<s.size();i++)
            {
                temp=temp*10+(s[i]-'0');
                if(temp>255)break;
                else
                {
                    count=count+1;
                    v1.push_back(temp);
                    ipdivide(i+1,s);
                    v1.pop_back();
                    count--;
                    if(temp==0)break;
                }                
            }
        }
    }
};

犯的两个错误:一个是s[i]-'0'写成了s[depth]-'0';一个是未对s.size()判断导致judge large超时

原文地址:https://www.cnblogs.com/tgkx1054/p/3099847.html