二叉树判断相等,复制

1.递归判断相等

#include "stdafx.h"
#include<iostream>
using namespace std;
typedef struct BTreeNode
{
	int data;
	struct BTreeNode *lchild,*rchild;
}BTree;
int _tmain(int argc, _TCHAR* argv[])
{
	return 0;
}
bool equal(BTree *p,BTree *q)
{
	if(!p&&!q)return true;//若都为空
	else if(!p&&q||p&&!q||p->data!=q->data)
		return false;
	else return(equal(p->lchild,q->rchild),equal(p->rchild,q->rchild));
}

 2.递归复制

BTree *Copy(BTree *t)
{
	BTree *bt;
	if(t==NULL)bt=NULL;//若为空
	else 
		{
			bt=(BTree*)malloc(sizeof(BTreeNode));
			bt->data=t->data;
			bt->lchild=Copy(t->lchild);
			bt->rchild=Copy(t->rchild);
	}
	return bt;
}

 3.非递归遍历

BTree *Copy(BTree *t)
{
	typedef struct
	{
		BTree *t;
		BTree *bt;
	} node;
	BTree *bt;
	node q[100];
	if(t==NULL){bt=NULL;return bt;}//若为空
	else 
		{
			QueueIn(Q,(t,bt));
			while(!QueueEmpty(Q))
			{
				(t,bt)=QueueOut(Q);
			bt=(BTree*)malloc(sizeof(BTreeNode));
			bt->data=t->data;
			if(t->lchild)QueueIn(Q,(t->lchild,bt->lchild));else  bt->lchild=NULL;
			if(t->rchild)QueueIn(Q,(t->rchild,bt->lchild));else  bt->rchild=NULL;
	}
	return bt;
}
原文地址:https://www.cnblogs.com/tgkx1054/p/2639075.html