openwrt的GPIO控制

为什么有些GPIO可以在/sys/class/gpio中控制,而有些不行呢?

先来看一看普通不需要C程序而是使用脚本的控制方法(Linux普遍适用):

First step is making GPIO available in Linux:

echo "29" > /sys/class/gpio/export

then you need to decide if it will be input or output, as we will use it as a switch so we need output

echo "out" > /sys/class/gpio/gpio29/direction

and last line turns GPIO on or off with 1 or 0:

echo "1" > /sys/class/gpio/gpio29/value

ath79_gpio_function_disable这个函数的作用是?

/* Enable GPIO15 and GPIO16 and possibly GPIO26 and GPIO27 */
ath79_gpio_function_disable(AR933X_GPIO_FUNC_ETH_SWITCH_LED2_EN |
                            AR933X_GPIO_FUNC_ETH_SWITCH_LED3_EN);

现象:当屏蔽掉上面两行之后,我的使用了GPIO15的程序就出错了!所以这个函数是使能某GPIO口的意思。

ath79_gpio_function_xxx在哪里定义?

ath79/gpio.c:159:void ath79_gpio_function_setup(u32 set, u32 clear)
ath79/gpio.c:173:void ath79_gpio_function_enable(u32 mask)
ath79/gpio.c:175:    ath79_gpio_function_setup(mask, 0);
ath79/gpio.c:178:void ath79_gpio_function_disable(u32 mask)
ath79/gpio.c:180:    ath79_gpio_function_setup(0, mask);

我们先看一下AR9331的数据手册,关于GPIO15和GPIO16:

当BIT(5),也就是AR933X_GPIO_FUNC_ETH_SWITCH_LED2_EN为1时,GPIO_15会作为以太网交换机的LED使用。而上面我们的函数是ath79_gpio_function_disable,意思就是不把这两个GPIO作为以太网交换机的LED使用,因而后面它可以被用作普通的GPIO口了!

上面这个寄存器的名字叫做GPIO_FUNCTION_1,其地址是0x18040028,reset值为0x00,因而开机的时候它都是GPIO口功能的。

这个寄存器的一小部分定义在openwrt1407/target/linux/ar71xx/image/lzma-loader/src/ar71xx_regs.h,摘抄其中相关的一些宏定义:

#define AR933X_GPIO_FUNC_SPDIF2TCK        BIT(31)
#define AR933X_GPIO_FUNC_SPDIF_EN        BIT(30)
#define AR933X_GPIO_FUNC_I2SO_22_18_EN        BIT(29)
#define AR933X_GPIO_FUNC_I2S_MCK_EN        BIT(27)
#define AR933X_GPIO_FUNC_I2SO_EN        BIT(26)
#define AR933X_GPIO_FUNC_ETH_SWITCH_LED_DUPL    BIT(25)
#define AR933X_GPIO_FUNC_ETH_SWITCH_LED_COLL    BIT(24)
#define AR933X_GPIO_FUNC_ETH_SWITCH_LED_ACT    BIT(23)
#define AR933X_GPIO_FUNC_SPI_EN            BIT(18)
#define AR933X_GPIO_FUNC_SPI_CS_EN2        BIT(14)
#define AR933X_GPIO_FUNC_SPI_CS_EN1        BIT(13)
#define AR933X_GPIO_FUNC_ETH_SWITCH_LED4_EN    BIT(7)
#define AR933X_GPIO_FUNC_ETH_SWITCH_LED3_EN    BIT(6)
#define AR933X_GPIO_FUNC_ETH_SWITCH_LED2_EN    BIT(5)
#define AR933X_GPIO_FUNC_ETH_SWITCH_LED1_EN    BIT(4)
#define AR933X_GPIO_FUNC_ETH_SWITCH_LED0_EN    BIT(3)
#define AR933X_GPIO_FUNC_UART_RTS_CTS_EN    BIT(2)
#define AR933X_GPIO_FUNC_UART_EN        BIT(1)
#define AR933X_GPIO_FUNC_JTAG_DISABLE        BIT(0)

经查找,在~../linux-3-10-49/arch/mips/dev-common.c中有一个对UART的IO口配置工作:

void __init ath79_register_uart(void)
{
    struct clk *clk;

    clk = clk_get(NULL, "uart");
    if (IS_ERR(clk))
        panic("unable to get UART clock, err=%ld", PTR_ERR(clk));

    if (soc_is_ar71xx())
        ath79_gpio_function_enable(AR71XX_GPIO_FUNC_UART_EN);
    else if (soc_is_ar724x())
        ath79_gpio_function_enable(AR724X_GPIO_FUNC_UART_EN);
    else if (soc_is_ar913x())
        ath79_gpio_function_enable(AR913X_GPIO_FUNC_UART_EN);
    else if (soc_is_ar933x())
        ath79_gpio_function_enable(AR933X_GPIO_FUNC_UART_EN);

    if (soc_is_ar71xx() ||
        soc_is_ar724x() ||
        soc_is_ar913x() ||
        soc_is_ar934x() ||
        soc_is_qca953x() ||
        soc_is_qca955x()) {
        ath79_uart_data[0].uartclk = clk_get_rate(clk);
        platform_device_register(&ath79_uart_device);
    } else if (soc_is_ar933x()) {
        ar933x_uart_data.uartclk = clk_get_rate(clk);
        platform_device_register(&ar933x_uart_device);
    } else {
        BUG();
    }
}
原文地址:https://www.cnblogs.com/tfanalysis/p/4206513.html