这个作业属于哪个课程 |
<a href="https://edu.cnblogs.com/campus/zswxy/CST2019-1/"target=_blank">《c语音程序设计》 |
这个作业要求在哪里 |
<a href="https://edu.cnblogs.com/campus/zswxy/CST2019-1/homework/10280"target=_blank">《C语言寒假大作战04 》 |
我在这个课程目标是 |
复习if语句的用法 |
参考文献 |
无 |
设计思路和遇到的问题
问题:认为可以直接定义的symbol参与计算
设计思路:用if语句来分出几种情况来继续,分别计算出每种情况下的答案。
程序截图:
一年级
二年级
三年级
2.2.4 程序代码
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
void Operationlist();
void firstgrade();
void secondgrade();
void gradethree();
void help();
void qiut();
void error();
int menu()
{
printf("========== 口算生成器 ==========
欢迎使用口算生成器 :
");
help();
Operationlist();
int n;
scanf("%d",&n);
return n;
}
int main(void)
{
int i=menu();
int flag=1;
while(flag==1){
switch(i){
case 1:firstgrade();break;
case 2:secondgrade();break;
case 3:gradethree();break;
case 4:help();break;
case 5:printf("
程序结束, 欢迎下次使用
任意键结束……");qiut();break;
default:error();break;
}
Operationlist();
scanf("%d",&i);
}
return 0;
}
void Operationlist()
{
printf("
操作列表:
1)一年级 2)二年级 3)三年级
4)帮助 5)退出程序
请输入操作>");
}
void firstgrade()
{
int i,t,x,randomnumber1,randomnumber2,sum;
char symbol;
printf("
现在是一年级的题目:
生产题目个数:");
scanf("%d",&i);
srand((unsigned)time(NULL));
for(x=0;i>x;x++){
t=rand()%2;
randomnumber1=rand()%10,randomnumber2=rand()%10;
if(t==0){
symbol='+';
sum=randomnumber1+randomnumber2;
}
else{
symbol='-';
sum=randomnumber1-randomnumber2;
}
printf("%d %c %d =%d
",randomnumber1,symbol,randomnumber2,sum);
}
}
void secondgrade()
{
int i,t,x,randomnumber1,randomnumber2;
char symbol;
double sum;
printf("
现在是二年级的题目:
生产题目个数:");
scanf("%d",&i);
srand((unsigned)time(NULL));
for(x=0;i>x;x++){
t=rand()%2;
if(t==0){
symbol='*';
}
else{
symbol='/';
}
if(symbol=='/'){
randomnumber1=rand()%100,randomnumber2=rand()%100+1;
sum=randomnumber1*1.0/randomnumber2;
}
else{
randomnumber1=rand()%100,randomnumber2=rand()%100;
sum=randomnumber1*randomnumber2;
}
printf("%d %c %d =%.6f
",randomnumber1,symbol,randomnumber2,sum);
}
}
void gradethree()
{
int i,t1,t2,x,randomnumber1,randomnumber2,randomnumber3;
char symbol1,symbol2;
double sum;
char symbol[4]={'+','-','*','/'};
printf ("
现在是三年级的题目:
生产题目个数:");
scanf("%d",&i);
srand((unsigned)time(NULL));
for(x=0;i>x;x++){
t1=rand()%4;
t2=rand()%4;
symbol1=symbol[t1];
symbol2=symbol[t2];
if(symbol1=='/'&&symbol2=='/'){
randomnumber1=rand()%100,randomnumber2=rand()%100+1,randomnumber3=rand()%100+1;
sum=randomnumber1*1.0/randomnumber2*1.0/randomnumber3;
}
else{
if(symbol1!='/'&&symbol2=='/'){
randomnumber1=rand()%100,randomnumber2=rand()%100,randomnumber3=rand()%100+1;
if(symbol1=='-'){
sum=randomnumber1-randomnumber2/randomnumber3;
}
else{
if(symbol1=='+'){
sum=randomnumber1+randomnumber2/randomnumber3;
}
else{
sum=randomnumber1*randomnumber2/randomnumber3;
}
}
}
else{
if(symbol1=='/'&&symbol2!='/'){
randomnumber1=rand()%100,randomnumber2=rand()%100+1,randomnumber3=rand()%100;
if(symbol2=='-'){
sum=randomnumber1/randomnumber2-randomnumber3;
}
else{
if(symbol2=='+'){
sum=randomnumber1/randomnumber2+randomnumber3;
}
else{
sum=randomnumber1/randomnumber2*randomnumber3;
}
}
}
else{
randomnumber1=rand()%100,randomnumber2=rand()%100,randomnumber3=rand()%100;
if(symbol1=='+'&&symbol2=='+'){
sum=randomnumber1+randomnumber2+randomnumber3;
}
else{
if(symbol1=='+'&&symbol2=='-'){
sum=randomnumber1+randomnumber2-randomnumber3;
}
else{
sum=randomnumber1+randomnumber2*randomnumber3;
}
}
if(symbol1=='-'&&symbol2=='+'){
sum=randomnumber1-randomnumber2+randomnumber3;
}
else{
if(symbol1=='-'&&symbol2=='-'){
sum=randomnumber1-randomnumber2-randomnumber3;
}
else{
sum=randomnumber1-randomnumber2*randomnumber3;
}
}
if(symbol1=='*'&&symbol2=='+'){
sum=randomnumber1*randomnumber2+randomnumber3;
}
else{
if(symbol1=='*'&&symbol2=='-'){
sum=randomnumber1*randomnumber2-randomnumber3;
}
else{
sum=randomnumber1*randomnumber2*randomnumber3;
}
}
}
}
}
printf("%d %c %d %c %d=%.6f
",randomnumber1,symbol1,randomnumber2,symbol2,randomnumber3,sum);
}
}
void help()
{
printf("
帮助信息
您需要输入命令代号来进行操作,
且一年级题目为不超过十位的加减法;
二年级题目为不超过百位的乘除法;
三年级题目为不超过百位的加减乘除混合题目.
");
}
void error()
{
printf("
Error!!!
错误操作指令, 请重新输入
");
}
void qiut()
{
exit(0);
}
Gitee上传截图与链接
截图
链接
https://gitee.com/tang_yan_wen/tang20199198