ccccccccccc

#include <math.h>
int main()
{
    int a,b,c,n;
    double x1,x2,x;
    scanf("%d,%d,%d",&a,&b,&c);
    if(a=0)
    {
        printf("Error!");
        exit(0);
    }
    if(b*b-4*a*c<0)
    {
        printf("No solution!");
        exit(0);
    }
    x1=x=(-b+sqrt(b*b-4*a*c))/(2*a);
    x2=(-b-sqrt(b*b-4*a*c))/(2*a);
    if(b*b-4*a*c>0)
    printf("x1=%6f,x2=%6f",x1,x2);
    else
    printf("x=%6f",x);
    return 0;
}
原文地址:https://www.cnblogs.com/tangxumin25/p/3447057.html