解决 for xml path encode 的问题

select

 stuff(

    (select ', <' + name + '>'

    from sys.databases

    where database_id > 4

    order by name

    for xml path(''), type

    ).value('(./text())[1]','varchar(max)')

  , 1, 2, '') as namelist;

原文地址:https://www.cnblogs.com/tangruixin/p/4490521.html