数据结构与算法分析 3.12 — 单链表转置

题目一:  不含头结点的单链表转置,算法时间复杂度O(N)

代码如下

struct LNode;
typedef struct LNode *List;
typedef struct LNode *Position;
struct LNode
{
    ElementType elem;
    Position next;
};

/* 无头结点单链表转置 */
List Reversion(List L)
{
    Position previousPos, currentPos, nextPos;

    previousPos = nullptr;
    currentPos = L;
    nextPos = L->next;

    while (nextPos != nullptr)
    {
        currentPos->next = previousPos;
        previousPos = currentPos;
        currentPos = nextPos;
        nextPos = nextPos->next;
    }
    currentPos->next = previousPos;
    return currentPos;
}

题目二: 带头结点的单链表转置,算法时间复杂度O(N)

struct LNode;
typedef struct LNode *List;
typedef struct LNode *Position;
struct LNode
{
    ElementType elem;
    Position next;
};

/* 带头结点单链表转置 */
List Reversion(List list)
{
    List header = list;
    List currentPos = header->next;

    header->next = nullptr;
    while (currentPos != nullptr)
    {
        Position tmp = currentPos;
        currentPos = currentPos->next;
        tmp->next = header->next;
        header->next = tmp;
    }
    return header;
}
原文地址:https://www.cnblogs.com/tallisHe/p/4214197.html