LeetCode-Convert Sorted List to Binary Search Tree

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode * CreateNode(vector<int>&vals,int start,int end){
        if(start>end)return NULL;
        int mid=(start+end)/2;
        TreeNode* ret=new TreeNode(vals[mid]);
        ret->left=CreateNode(vals,start,mid-1);
        ret->right=CreateNode(vals,mid+1,end);
    }
    TreeNode *sortedListToBST(ListNode *head) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        vector<int> values;
        while(head!=NULL){
            values.push_back(head->val);
            head=head->next;
        }
        return CreateNode(values,0,values.size()-1);
    }
};
原文地址:https://www.cnblogs.com/superzrx/p/3323545.html