Rectangle Area

Rectangle Area

问题：

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Assume that the total area is never beyond the maximum possible value of int.
思路：

　　数学的推导计算

我的代码：

public class Solution {
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int oneArea = (C-A)*(D-B);
        int twoArea = (G-E)*(H-F);
        int left = Math.max(A, E);
        int right = Math.min(C, G);
        int down = Math.max(B, F);
        int top = Math.min(D, H);
        int intersect = 0;
        if(left < right && down < top)
            intersect = (right-left)*(top-down);
        return oneArea + twoArea - intersect;
    }
}

学习之处：

• 是看了别人的代码才想到了怎么做，因为之前自己的代码太挫了，必须通过各种if else才能得到两个矩形的关系，别人的方法是通过左边界，右边界，上边界，下边界确定了矩形的面试，值得学习。