UVa 11389

题意:有n个早晨的班车和下午的班车,分配给司机,如果工作总时间超过d,超过的部分要给加班费;求最小的加班分花费。

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<algorithm>
 4 
 5 using namespace std;
 6 
 7 int morning[101];
 8 int after[101];
 9 
10 bool cmp1(int a,int b)
11 {
12     return a<b;
13 }
14 bool cmp2(int a,int b)
15 {
16     return a>b;
17 }
18 
19 int main()
20 {
21     int n,d,r;
22     while(scanf("%d%d%d",&n,&d,&r)!=EOF)
23     {
24         if(n+d+r==0)
25         break;
26         for(int i=0;i<n;++i)
27             scanf("%d",&morning[i]);
28         for(int i=0;i<n;++i)
29             scanf("%d",&after[i]);
30         sort(morning,morning+n,cmp1);
31         sort(after,after+n,cmp2);
32         int sum=0;
33         for(int i=0;i<n;++i)
34             if (morning[i]+after[i]>d)
35                 sum+=r*(morning[i]+after[i]-d);
36         printf("%d
",sum);
37     }
38     return 0;
39 }
原文地址:https://www.cnblogs.com/sunshinemxh/p/4851143.html