【leetcode】Clone Graph

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.


OJ's undirected graph serialization:

Nodes are labeled uniquely.

We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.

As an example, consider the serialized graph {0,1,2#1,2#2,2}.

The graph has a total of three nodes, and therefore contains three parts as separated by #.

  1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
  2. Second node is labeled as 1. Connect node 1 to node 2.
  3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.

Visually, the graph looks like the following:

       1
      / 
     /   
    0 --- 2
         / 
         \_/

题解:利用DFS递归的方法克隆图,用hashmap保存原图中的节点和新图中的节点的对应关系。而且利用这个hashmap可以在O(1)的时间内判断一个节点是否被克隆过,并且知道克隆它得到的新节点。

实现一个克隆节点的方法,在这个方法中:

  1. 判断这个节点是否被clone过了,如果是,返回它对应的clone节点;
  2. 如果没有被clone过,那么新建节点为该节点的clone节点,并且递归的clone它的邻居节点,放入该节点的neighbors列表里面;

代码如下:

 1 /**
 2  * Definition for undirected graph.
 3  * class UndirectedGraphNode {
 4  *     int label;
 5  *     List<UndirectedGraphNode> neighbors;
 6  *     UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
 7  * };
 8  */
 9 public class Solution {
10     private HashMap<UndirectedGraphNode,UndirectedGraphNode> mapClone = new HashMap<UndirectedGraphNode,UndirectedGraphNode>();
11     
12     private UndirectedGraphNode cloneNode(UndirectedGraphNode node){
13         if(node == null)
14             return null;
15         //if this node already has a clone
16         if(mapClone.containsKey(node))
17             return mapClone.get(node);
18         
19         //if this node hasn't been cloned, we construct a new node copy
20         UndirectedGraphNode copy = new UndirectedGraphNode(node.label);
21         mapClone.put(node, copy);
22         
23         //clone all the neighbers of node
24         for(UndirectedGraphNode n:node.neighbors){
25             copy.neighbors.add(cloneNode(n));
26         }
27         return copy;
28     }
29     public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
30         return cloneNode(node);
31     }
32 }
原文地址:https://www.cnblogs.com/sunshineatnoon/p/3854707.html