【leetcode刷题笔记】N-Queens II

Follow up for N-Queens problem.

Now, instead outputting board configurations, return the total number of distinct solutions.


题解:参见http://www.cnblogs.com/sunshineatnoon/p/3853170.html

只要求求出解的个数,稍微改一下代码就可以了:用私有变量result记录解的数目,当搜索到一个解的时候,result+1即可。

代码如下:

 1 public class Solution {
 2 private int result = 0;
 3     private boolean isValid(List<Integer> cols,int col){
 4         for(int i = 0;i < cols.size();i++){
 5             if(cols.get(i) == col)
 6                 return false;
 7             if(cols.size() - i == Math.abs(cols.get(i) - col))
 8                 return false;
 9         }
10         return true;
11     }
12     private void QueenDfs(int n,int level,List<Integer> cols){
13         if(level == n){
14             result++;
15         }
16         
17         for(int i = 0;i < n;i++){
18             if(isValid(cols, i)){
19                 cols.add(i);
20                 QueenDfs(n, level+1, cols);
21                 cols.remove(cols.size()-1);
22             }
23         }
24     }
25     public int totalNQueens(int n) {
26 
27         List<Integer> cols = new ArrayList<Integer>();
28         QueenDfs(n, 0, cols );
29         
30         return result;
31     }
32 }
原文地址:https://www.cnblogs.com/sunshineatnoon/p/3853191.html