飘逸的python

python拥有这种单独起一个服务器监听端口的能力,用标准库的wsgiref就行。

from wsgiref.simple_server import make_server
def simple_app(environ, start_response):
    status = '200 OK'
    response_headers = [('Content-type','text/plain')]
    start_response(status, response_headers)
    return ['Hello world!
']
httpd = make_server('', 80, simple_app)
httpd.serve_forever()


原文地址:https://www.cnblogs.com/suncoolcat/p/3320083.html