Learn Python the hard way, ex39 列表的操作

 1 #!/usr/bin/python
 2 #coding:utf-8
 3 
 4 ten_things = "apples oranges crows telephone light sugar"
 5 print "wait there's not 10 things in that list,let's fix that"
 6 
 7 stuff = ten_things.split(' ')  #10个东西,以' '间隔开
 8 more_stuff = ["day","night","song","frisbee","corn","banana","girl","boy"]  #更多的原料
 9 
10 while len(stuff) != 10:  #取得List stuff的长度,当不等于10时循环
11     next_one = more_stuff.pop()    #截取more_stuff的最后一个元素(默认值)
12     print "adding:",next_one    #输出pop取得的值
13     stuff.append(next_one)     #使用append将之前截取的值赋予list:stuff
14     print "there's %d items now" % len(stuff)
15 
16 print "there we go : ",stuff
17 
18 print "let's do some things with stuff"
19 
20 print stuff[1]  #第二个元素,list从0计数
21 print stuff[-1]  #whoa!fancy   最后一个元素(-1)
22 print stuff.pop()
23 print ' '.join(stuff)  #what?cool!
24 print '#'.join(stuff[3:5])  # super stellar

Output:

 1 wait there's not 10 things in that list,let's fix that
 2 adding: boy
 3 there's 7 items now
 4 adding: girl
 5 there's 8 items now
 6 adding: banana
 7 there's 9 items now
 8 adding: corn
 9 there's 10 items now
10 there we go :  ['apples', 'oranges', 'crows', 'telephone', 'light', 'sugar', 'boy', 'girl', 'banana', 'corn']
11 let's do some things with stuff
12 oranges
13 corn
14 corn
15 apples oranges crows telephone light sugar boy girl banana
16 telephone#light

join()

加分题的一些参考: Python 面向对象编程 函数式编程

原文地址:https://www.cnblogs.com/sub2020/p/7865363.html