C# post请求 HttpWebRequest

1.参数 paramsValue的格式 要和 Reques.ContentType一致，

如果 contentype "application/x-www-form-urlencoded" 表单类型，那么 参数为 a=1&b=2 形式

如果 。。。 "application/json" json 类型 那么参数就为 "{a:1,b:2}" 格式

接收json

Stream postData = Request.InputStream;
StreamReader sRead = new StreamReader(postData);
string postContent = sRead.ReadToEnd();
sRead.Close();

//body是要传递的参数,格式"roleId=1&uid=2"
//post的cotentType填写:
//"application/x-www-form-urlencoded"
//soap填写:"text/xml; charset=utf-8"

        public  string PostHttp(string url, string body, string contentType)
        {
            HttpWebRequest httpWebRequest = (HttpWebRequest)WebRequest.Create(url);
 
            httpWebRequest.ContentType = contentType;
            httpWebRequest.Method = "POST";
            httpWebRequest.Timeout = 20000;
 
            byte[] btBodys = Encoding.UTF8.GetBytes(body);
            httpWebRequest.ContentLength = btBodys.Length;
            httpWebRequest.GetRequestStream().Write(btBodys, 0, btBodys.Length);
 
            HttpWebResponse httpWebResponse = (HttpWebResponse)httpWebRequest.GetResponse();
            StreamReader streamReader = new StreamReader(httpWebResponse.GetResponseStream());
            string responseContent = streamReader.ReadToEnd();
 
            httpWebResponse.Close();
            streamReader.Close();
            httpWebRequest.Abort();
            httpWebResponse.Close();
 
            return responseContent;
        }