[Swift]LeetCode1296. 划分数组为连续数字的集合 | Divide Array in Sets of K Consecutive Numbers

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Given an array of integers nums and a positive integer k, find whether it's possible to divide this array into sets of k consecutive numbers
Return True if its possible otherwise return False.

Example 1:

Input: nums = [1,2,3,3,4,4,5,6], k = 4
Output: true
Explanation: Array can be divided into [1,2,3,4] and [3,4,5,6].
Example 2:

Input: nums = [3,2,1,2,3,4,3,4,5,9,10,11], k = 3
Output: true
Explanation: Array can be divided into [1,2,3] , [2,3,4] , [3,4,5] and [9,10,11].
Example 3:

Input: nums = [3,3,2,2,1,1], k = 3
Output: true
Example 4:

Input: nums = [1,2,3,4], k = 3
Output: false
Explanation: Each array should be divided in subarrays of size 3.
 

Constraints:

1 <= nums.length <= 10^5
1 <= nums[i] <= 10^9
1 <= k <= nums.length


给你一个整数数组 nums 和一个正整数 k,请你判断是否可以把这个数组划分成一些由 k 个连续数字组成的集合。
如果可以,请返回 True;否则,返回 False。

示例 1:

输入:nums = [1,2,3,3,4,4,5,6], k = 4
输出:true
解释:数组可以分成 [1,2,3,4] 和 [3,4,5,6]。
示例 2:

输入:nums = [3,2,1,2,3,4,3,4,5,9,10,11], k = 3
输出:true
解释:数组可以分成 [1,2,3] , [2,3,4] , [3,4,5] 和 [9,10,11]。
示例 3:

输入:nums = [3,3,2,2,1,1], k = 3
输出:true
示例 4:

输入:nums = [1,2,3,4], k = 3
输出:false
解释:数组不能分成几个大小为 3 的子数组。
 

提示:

1 <= nums.length <= 10^5
1 <= nums[i] <= 10^9
1 <= k <= nums.length

原文地址:https://www.cnblogs.com/strengthen/p/12151619.html