【BZOJ3413】—匹配(后缀自动机+线段树合并)

传送门

相当于对每个询问串询问和一堆串的lcplcp

考虑对询问串的每一位ii分别考虑会和多少个串匹配到这一位
假设最后末尾在pp匹配上
那显然就是当前这一位对应的节点的endposendpos[i,p+ilen][i,p+i-len]范围内
如果一直没匹配上就是[i,n][i,n]

然后线段树合并维护endposendpos就完了

#include<bits/stdc++.h>
using namespace std;
const int RLEN=1<<20|1;
inline char gc(){
    static char ibuf[RLEN],*ib,*ob;
    (ob==ib)&&(ob=(ib=ibuf)+fread(ibuf,1,RLEN,stdin));
    return (ob==ib)?EOF:*ib++;
}
#define gc getchar
inline int read(){
    char ch=gc();
    int res=0,f=1;
    while(!isdigit(ch))f^=ch=='-',ch=gc();
    while(isdigit(ch))res=(res+(res<<2)<<1)+(ch^48),ch=gc();
    return f?res:-res;
}
#define ll long long
#define re register
#define pii pair<int,int>
#define pic pair<int,char>
#define fi first
#define se second
#define pb push_back
#define cs const
#define bg begin
#define poly vector<int>
template<class T>inline void chemx(T &a,T &b){a<b?a=b:0;}
template<class T>inline void chemn(T &a,T &b){a>b?a=b:0;}
cs int N=100005;
int n,m;
namespace Seg{
	cs int M=N*50;
	int lc[M],rc[M],siz[M],tot;
	#define mid ((l+r)>>1)
	inline void insert(int &u,int l,int r,int p){
		u=++tot;siz[u]++;
		if(l==r)return;
		if(p<=mid)insert(lc[u],l,mid,p);
		else insert(rc[u],mid+1,r,p);
	}
	inline void merge(int &u,int r1,int r2){
		if(!r1||!r2){u=r1+r2;return;}
		u=++tot,siz[u]=siz[r1]+siz[r2];
		merge(lc[u],lc[r1],lc[r2]);
		merge(rc[u],rc[r1],rc[r2]);
	}
	inline int query(int u,int l,int r,int st,int des){
		if(!u)return 0;
		if(st<=l&&r<=des)return siz[u];
		int res=0;
		if(st<=mid)res+=query(lc[u],l,mid,st,des);
		if(mid<des)res+=query(rc[u],mid+1,r,st,des);
		return res;
	}
}
namespace Sam{
	cs int M=N*2;
	int len[M],fa[M],nxt[M][10],pos[M],ed[N],rt[M];
	int tot,last;
	inline void init(){
		tot=last=1;
	}
	inline void insert(int c,int id){
		int cur=++tot,p=last;last=cur;
		ed[id]=cur,pos[cur]=id;
		len[cur]=len[p]+1;
		for(;p&&!nxt[p][c];p=fa[p])nxt[p][c]=cur;
		if(!p)fa[cur]=1;
		else{
			int q=nxt[p][c];
			if(len[p]+1==len[q])fa[cur]=q;
			else{
				int clo=++tot;
				fa[clo]=fa[q],len[clo]=len[p]+1;
				memcpy(nxt[clo],nxt[q],sizeof(nxt[q]));
				for(;p&&nxt[p][c]==q;p=fa[p])nxt[p][c]=clo;
				fa[cur]=fa[q]=clo;
			}
		}
	}
	int buc[M],rk[M];
	inline void build(){
		for(int i=1;i<=tot;i++)buc[len[i]]++;
		for(int i=1;i<=tot;i++)buc[i]+=buc[i-1];
		for(int i=1;i<=tot;i++)rk[buc[len[i]]--]=i;
		for(int i=tot;i>=1;i--){
			int u=rk[i];
			if(pos[u])Seg::insert(rt[u],1,n,pos[u]);
			Seg::merge(rt[fa[u]],rt[fa[u]],rt[u]);
			if(!pos[u])pos[u]=1e9;
		}
		for(int i=tot;i>=1;i--){
			int u=rk[i];
			chemn(pos[fa[u]],pos[u]);
		}
	}
	inline ll query(char *s){
		ll res=0;int p=1,fg=0,l=strlen(s+1),lim;
		for(int i=1;i<=l;i++){
			int c=s[i]-'0';
			if(!nxt[p][c]){fg=1;break;}
			p=nxt[p][c];
		}
		if(fg==1)res=n,lim=n;
		else lim=pos[p],res=(lim-l);
		p=1;
		for(int i=1;i<=l;i++){
			int c=s[i]-'0';
			if(!nxt[p][c])break;
			p=nxt[p][c];
			res+=Seg::query(rt[p],1,n,i,fg?n:(lim+i-l));
		}
		return res;
	}
}
char s[N];
int main(){
	Sam::init();
	n=read();
	scanf("%s",s+1);
	for(int i=1;i<=n;i++)Sam::insert(s[i]-'0',i);
	Sam::build();
	m=read();
	for(int i=1;i<=m;i++){
		scanf("%s",s+1);
		cout<<Sam::query(s)<<'
';
	}
}
原文地址:https://www.cnblogs.com/stargazer-cyk/p/12328441.html