94. Binary Tree Inorder Traversal

该题目是要将树进行中序遍历。理解了中序遍历的原理,就知道如何解答这一题目了。中序遍历就是首先遍历先遍历左节点,然后根节点,最后右节点。

代码如下:

 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     int val;
 5  *     TreeNode left;
 6  *     TreeNode right;
 7  *     TreeNode(int x) { val = x; }
 8  * }
 9  */
10 class Solution {
11     public List<Integer> inorderTraversal(TreeNode root) {
12         List<Integer> res = new ArrayList<Integer>();
13         
14         if(root == null){
15             return res;
16         }
17         
18         helper(root, res);
19         
20         return res;
21     }
22     
23     private void helper(TreeNode root, List<Integer> res ){
24         
25         if(root.left != null){
26             helper(root.left, res);
27         }
28         
29         res.add(root.val);
30         
31         if(root.right != null){
32             helper(root.right, res);
33         }
34     }
35 }

END

原文地址:https://www.cnblogs.com/sssysukww/p/8742907.html