shell 判断字符串是否包含另一个字符串

1.使用grep

s1="abcdefg"
s2="bcd"
result=$(echo $s1 | grep "${s2}")
if [[ "$result" != "" ]]
then
    echo "$s1 include $s2"
else
    echo "$1 not include $s2"
fi

2. 使用操作符~

fileName=/home/sss/data/hk

if [[ $fileName =~hk ]]
then
    echo "$fileName include hk"
else
    echo "not include"
fi

3. 使用通配符*

A="helloworld"
B="low"
if [[ $A == *$B* ]]
then
    echo "包含"
else
    echo "不包含"
fi
原文地址:https://www.cnblogs.com/sssblog/p/10273148.html