JDK1.8源码TreeMap

基于红黑树(Red-Black tree)的 NavigableMap 实现;键的排序由构造方法决定:自然排序,Comparator排序;非线程安全(仅改变与现有键关联的值不是结构上的修改);线程安全的最好方法是在创建的时候包装成线程安全的

1 SortedMap m = Collections.synchronizedSortedMap(new TreeMap(...));

迭代器与LinkedList相似。

构造器,基本属性:

 1 public class TreeMap<K,V>
 2     extends AbstractMap<K,V>
 3     implements NavigableMap<K,V>, Cloneable, java.io.Serializable
 4 {
 5 
 6     //比较器,如果是null就是自然顺序
 7     private final Comparator<? super K> comparator;
 8 
 9     //根Entry
10     private transient Entry<K,V> root;
11 
12     //Entry个数
13     private transient int size = 0;
14 
15     //结构性修改次数
16     private transient int modCount = 0;
17 
18     //构造一个空的tree map,使用键的自然顺序,键必须是实现了Comparable,
19     public TreeMap() {
20         comparator = null;
21     }
22 
23     //构造一个空的tree map,键按给定的比较器排序,
24     public TreeMap(Comparator<? super K> comparator) {
25         this.comparator = comparator;
26     }
27 
28     //构造一个与给定映射具有相同映射关系的新的tree map,该映射根据其键的自然顺序进行排序
29     public TreeMap(Map<? extends K, ? extends V> m) {
30         comparator = null;
31         putAll(m);
32     }
33    
34     //构造一个与给定映射具有相同映射关系的新的tree map,该映射根据其m的键的比较器进行排序
35     public TreeMap(SortedMap<K, ? extends V> m) {
36         comparator = m.comparator();
37         try {
38             buildFromSorted(m.size(), m.entrySet().iterator(), null, null);
39         } catch (java.io.IOException cannotHappen) {
40         } catch (ClassNotFoundException cannotHappen) {
41         }
42     }
43    。。。。。。
44 }
void putAll(Map<? extends K, ? extends V> map);

V put(K key, V value);

void fixAfterInsertion(Entry<K,V> x)
关于红黑树的详解可以参考这篇博文: https://www.cnblogs.com/CarpenterLee/p/5503882.html
有些概念的东西可以参考这篇博文: https://blog.csdn.net/sun_tttt/article/details/65445754
例如红黑树的删除,先寻找该结点的后继结点,然后互换值,但不互换颜色,最后再调整!
  1     //将指定映射中的所有映射关系复制到此映射中。这些映射关系将替换此映射所有当前为指定映射的所有键所包含的映射关系。 
  2     public void putAll(Map<? extends K, ? extends V> map) {
  3         int mapSize = map.size();
  4         if (size==0 && mapSize!=0 && map instanceof SortedMap) {//map是键有排序的map
  5             Comparator<?> c = ((SortedMap<?,?>)map).comparator();
  6             if (c == comparator || (c != null && c.equals(comparator))) {
  7                 ++modCount;
  8                 try {
  9                     buildFromSorted(mapSize, map.entrySet().iterator(),
 10                                     null, null);
 11                 } catch (java.io.IOException cannotHappen) {
 12                 } catch (ClassNotFoundException cannotHappen) {
 13                 }
 14                 return;
 15             }
 16         }
 17         super.putAll(map);//
 18     }
 19 
 20     AbstractMap抽象map的方法
 21     public void putAll(Map<? extends K, ? extends V> m) {
 22         for (Map.Entry<? extends K, ? extends V> e : m.entrySet())
 23             put(e.getKey(), e.getValue());
 24     }
 25     
 26     //将key和value存放在map里,如果map里有相同的key,旧的value被替换
 27     public V put(K key, V value) {
 28         Entry<K,V> t = root;//根节点
 29         if (t == null) {//如果根节点没有值,就把当前值作为根节点
 30             compare(key, key); // type (and possibly null) check
 31 
 32             root = new Entry<>(key, value, null);
 33             size = 1;
 34             modCount++;
 35             return null;
 36         }
 37         int cmp;
 38         Entry<K,V> parent;
 39         // split comparator and comparable paths
 40         Comparator<? super K> cpr = comparator;
 41         if (cpr != null) {//比较器不是空
 42             do {
 43                 parent = t;
 44                 cmp = cpr.compare(key, t.key);
 45                 if (cmp < 0)
 46                     t = t.left;
 47                 else if (cmp > 0)
 48                     t = t.right;
 49                 else
 50                     return t.setValue(value);
 51             } while (t != null);
 52         }
 53         else {//比较器是空,使用自然顺序比较器
 54             if (key == null)
 55                 throw new NullPointerException();
 56             @SuppressWarnings("unchecked")
 57                 Comparable<? super K> k = (Comparable<? super K>) key;
 58             do {
 59                 parent = t;
 60                 cmp = k.compareTo(t.key);//key与key的父的key比较
 61                 if (cmp < 0)//如果小于,节点在t的左侧
 62                     t = t.left;//将t置为t的左侧节点
 63                 else if (cmp > 0)
 64                     t = t.right;
 65                 else  //如果相等,新value替换旧value
 66                     return t.setValue(value);
 67             } while (t != null);//t节点不是空
 68         }
 69         Entry<K,V> e = new Entry<>(key, value, parent);
 70         if (cmp < 0)
 71             parent.left = e;
 72         else
 73             parent.right = e;
 74         fixAfterInsertion(e);//红黑树插入新结点后调整
 75         size++;
 76         modCount++;
 77         return null;
 78     }
 79     
 80     final int compare(Object k1, Object k2) {
 81         return comparator==null ? ((Comparable<? super K>)k1).compareTo((K)k2)
 82             : comparator.compare((K)k1, (K)k2);
 83     }
 84     
 85     //红黑树插入新结点后调整
 86     private void fixAfterInsertion(Entry<K,V> x) {
 87         x.color = RED;
 88 
 89         while (x != null && x != root && x.parent.color == RED) {//x的父的颜色是红色        
 90             if (parentOf(x) == leftOf(parentOf(parentOf(x)))) {//x的父==x的父的父的左侧
 91                 Entry<K,V> y = rightOf(parentOf(parentOf(x)));//y=x的父的父的右侧
 92                 if (colorOf(y) == RED) {//y的颜色是红色
 93                     setColor(parentOf(x), BLACK);//x的父置为黑色
 94                     setColor(y, BLACK);//y置为黑色
 95                     setColor(parentOf(parentOf(x)), RED);//x的父的父置为红色
 96                     x = parentOf(parentOf(x));//x=x的父的父
 97                 } else {//y的颜色是黑色
 98                     if (x == rightOf(parentOf(x))) {//x==x的父的右侧
 99                         x = parentOf(x);//x=x的父
100                         rotateLeft(x);//左旋
101                     }
102                     setColor(parentOf(x), BLACK);
103                     setColor(parentOf(parentOf(x)), RED);
104                     rotateRight(parentOf(parentOf(x)));//右旋
105                 }
106             } else {
107                 Entry<K,V> y = leftOf(parentOf(parentOf(x)));
108                 if (colorOf(y) == RED) {
109                     setColor(parentOf(x), BLACK);
110                     setColor(y, BLACK);
111                     setColor(parentOf(parentOf(x)), RED);
112                     x = parentOf(parentOf(x));
113                 } else {
114                     if (x == leftOf(parentOf(x))) {
115                         x = parentOf(x);
116                         rotateRight(x);
117                     }
118                     setColor(parentOf(x), BLACK);
119                     setColor(parentOf(parentOf(x)), RED);
120                     rotateLeft(parentOf(parentOf(x)));
121                 }
122             }
123         }
124         root.color = BLACK;
125     }
126     
127     //左旋
128     private void rotateLeft(Entry<K,V> p) {
129         if (p != null) {
130             Entry<K,V> r = p.right;
131             p.right = r.left;
132             if (r.left != null)
133                 r.left.parent = p;
134             r.parent = p.parent;
135             if (p.parent == null)
136                 root = r;
137             else if (p.parent.left == p)
138                 p.parent.left = r;
139             else
140                 p.parent.right = r;
141             r.left = p;
142             p.parent = r;
143         }
144     }
145 
146     //右旋
147     private void rotateRight(Entry<K,V> p) {
148         if (p != null) {
149             Entry<K,V> l = p.left;
150             p.left = l.right;
151             if (l.right != null) l.right.parent = p;
152             l.parent = p.parent;
153             if (p.parent == null)
154                 root = l;
155             else if (p.parent.right == p)
156                 p.parent.right = l;
157             else p.parent.left = l;
158             l.right = p;
159             p.parent = l;
160         }
161     }

 buildFromSorted:(待解决)

 1 //采用递归的思路,先构建后节点的左子树,在构建好节点的右子树,最后和节点组合成一个完整的子树。
 2     private void buildFromSorted(int size, Iterator<?> it,
 3                                  java.io.ObjectInputStream str,
 4                                  V defaultVal)
 5         throws  java.io.IOException, ClassNotFoundException {
 6         this.size = size;
 7         root = buildFromSorted(0, 0, size-1, computeRedLevel(size),
 8                                it, str, defaultVal);
 9     }
10     
11     
12     /**
13      * Recursive "helper method" that does the real work of the
14      * previous method.  Identically named parameters have
15      * identical definitions.  Additional parameters are documented below.
16      * It is assumed that the comparator and size fields of the TreeMap are
17      * already set prior to calling this method.  (It ignores both fields.)
18      *
19      * @param level the current level of tree. Initial call should be 0.//当前树的级别
20      * @param lo the first element index of this subtree. Initial should be 0.//子树的第一个元素
21      * @param hi the last element index of this subtree.  Initial should be //子树的最后一个元素
22      *        size-1.
23      * @param redLevel the level at which nodes should be red. 
24      *        Must be equal to computeRedLevel for tree of this size.
25      */
26     @SuppressWarnings("unchecked")
27     private final Entry<K,V> buildFromSorted(int level, int lo, int hi,
28                                              int redLevel,
29                                              Iterator<?> it,
30                                              java.io.ObjectInputStream str,
31                                              V defaultVal)
32         throws  java.io.IOException, ClassNotFoundException {
33         /*
34          * Strategy: The root is the middlemost element. To get to it, we
35          * have to first recursively construct the entire left subtree,
36          * so as to grab all of its elements. We can then proceed with right
37          * subtree.
38          *
39          * The lo and hi arguments are the minimum and maximum
40          * indices to pull out of the iterator or stream for current subtree.
41          * They are not actually indexed, we just proceed sequentially,
42          * ensuring that items are extracted in corresponding order.
43          */
44 
45         if (hi < lo) return null;
46 
47         int mid = (lo + hi) >>> 1;
48 
49         Entry<K,V> left  = null;
50         if (lo < mid)
51             left = buildFromSorted(level+1, lo, mid - 1, redLevel,
52                                    it, str, defaultVal);
53 
54         // extract key and/or value from iterator or stream
55         K key;
56         V value;
57         if (it != null) {
58             if (defaultVal==null) {
59                 Map.Entry<?,?> entry = (Map.Entry<?,?>)it.next();
60                 key = (K)entry.getKey();
61                 value = (V)entry.getValue();
62             } else {
63                 key = (K)it.next();
64                 value = defaultVal;
65             }
66         } else { // use stream
67             key = (K) str.readObject();
68             value = (defaultVal != null ? defaultVal : (V) str.readObject());
69         }
70 
71         Entry<K,V> middle =  new Entry<>(key, value, null);
72 
73         // color nodes in non-full bottommost level red
74         if (level == redLevel)
75             middle.color = RED;
76 
77         if (left != null) {
78             middle.left = left;
79             left.parent = middle;
80         }
81 
82         if (mid < hi) {
83             Entry<K,V> right = buildFromSorted(level+1, mid+1, hi, redLevel,
84                                                it, str, defaultVal);
85             middle.right = right;
86             right.parent = middle;
87         }
88 
89         return middle;
90     }

 Entry<K,V> getEntry(Object key);successor(Entry<K,V> t)

 1     //键值对个数
 2     public int size() {
 3         return size;
 4     }
 5 
 6     //是否包含指定的key
 7     public boolean containsKey(Object key) {
 8         return getEntry(key) != null;
 9     }
10 
11     final Entry<K,V> getEntry(Object key) {
12         // Offload comparator-based version for sake of performance
13         if (comparator != null)
14             return getEntryUsingComparator(key);
15         if (key == null)
16             throw new NullPointerException();
17         @SuppressWarnings("unchecked")
18             Comparable<? super K> k = (Comparable<? super K>) key;
19         Entry<K,V> p = root;
20         while (p != null) {
21             int cmp = k.compareTo(p.key);
22             if (cmp < 0) //key<p.key,p=p.left
23                 p = p.left;
24             else if (cmp > 0)//key>p.key,p=p.right
25                 p = p.right;
26             else      //key=p.key,key=p
27                 return p;
28         }
29         return null;
30     }
31     总结:比结点值大,向结点右边找,比结点值小,向结点左边找
32     
33     //使用指定的比较器查找key
34     final Entry<K,V> getEntryUsingComparator(Object key) {
35         @SuppressWarnings("unchecked")
36             K k = (K) key;
37         Comparator<? super K> cpr = comparator;
38         if (cpr != null) {
39             Entry<K,V> p = root;
40             while (p != null) {
41                 int cmp = cpr.compare(k, p.key);
42                 if (cmp < 0)
43                     p = p.left;
44                 else if (cmp > 0)
45                     p = p.right;
46                 else
47                     return p;
48             }
49         }
50         return null;
51     }
52      
53     //map是否含有指定的value 
54     public boolean containsValue(Object value) {
55         for (Entry<K,V> e = getFirstEntry(); e != null; e = successor(e))
56             if (valEquals(value, e.value))
57                 return true;
58         return false;
59     }
60     
61     //返回treemap的第一个结点,如果treemap是null,则返回null
62     final Entry<K,V> getFirstEntry() {
63         Entry<K,V> p = root;
64         if (p != null)
65             while (p.left != null)
66                 p = p.left;
67         return p;
68     }
69 
70     //寻找结点后继
71     static <K,V> TreeMap.Entry<K,V> successor(Entry<K,V> t) {
72         if (t == null)
73             return null;
74         else if (t.right != null) {
75             Entry<K,V> p = t.right;
76             while (p.left != null)
77                 p = p.left;
78             return p;
79         } else {
80             Entry<K,V> p = t.parent;
81             Entry<K,V> ch = t;
82             while (p != null && ch == p.right) {
83                 ch = p;
84                 p = p.parent;
85             }
86             return p;
87         }
88     }
89     
90     总结:t的右子树不空,则t的后继是其右子树中最小的那个元素。
91           t的右孩子为空,则t的后继是其第一个向左走的祖先。

getCeilingEntry, getFloorEntry, getHigherEntry, getLowerEntry

  1     //两个值是否相等 
  2     static final boolean valEquals(Object o1, Object o2) {
  3         return (o1==null ? o2==null : o1.equals(o2));
  4     }      
  5      
  6     //指定的key返回value ,如果map不包含key,返回null
  7     public V get(Object key) {
  8         Entry<K,V> p = getEntry(key);
  9         return (p==null ? null : p.value);
 10     }
 11 
 12     //查询treemap比较器
 13     public Comparator<? super K> comparator() {
 14         return comparator;
 15     }
 16 
 17     //返回treemap的第一个结点的key,如果是null,抛出错误
 18     public K firstKey() {
 19         return key(getFirstEntry());
 20     }
 21 
 22     //返回treemap的最后一个结点的key,如果是null,抛出错误
 23     public K lastKey() {
 24         return key(getLastEntry());
 25     }
 26 
 27     //返回treemap的最后一个结点,如果treemap是null,则返回null
 28     final Entry<K,V> getLastEntry() {
 29         Entry<K,V> p = root;
 30         if (p != null)
 31             while (p.right != null)
 32                 p = p.right;
 33         return p;
 34     }
 35    
 36     public Map.Entry<K,V> ceilingEntry(K key) {
 37         return exportEntry(getCeilingEntry(key));
 38     }
 39     
 40     //返回一个简单的不可变的结点
 41     static <K,V> Map.Entry<K,V> exportEntry(TreeMap.Entry<K,V> e) {
 42         return (e == null) ? null :
 43             new AbstractMap.SimpleImmutableEntry<>(e);
 44     }
 45     
 46     AbstractMap类
 47     //以指定的结点创建一个相同的结点
 48     public SimpleImmutableEntry(Entry<? extends K, ? extends V> entry) {
 49         this.key   = entry.getKey();
 50         this.value = entry.getValue();
 51     }
 52     
 53     public K ceilingKey(K key) {
 54         return keyOrNull(getCeilingEntry(key));
 55     }
 56      
 57     static <K,V> K keyOrNull(TreeMap.Entry<K,V> e) {
 58         return (e == null) ? null : e.key;
 59     }
 60     
 61     
 62     //指定的key返回结点;如果没有,则返回比key大的最小的结点;
 63     //若不存在(即TreeMap中所有节点的键都比key大),就返回null”
 64     final Entry<K,V> getCeilingEntry(K key) {
 65         Entry<K,V> p = root;
 66         while (p != null) {
 67             int cmp = compare(key, p.key);
 68             if (cmp < 0) {
 69                 if (p.left != null)
 70                     p = p.left;
 71                 else
 72                     return p;
 73             } else if (cmp > 0) {
 74                 if (p.right != null) {
 75                     p = p.right;
 76                 } else {
 77                     Entry<K,V> parent = p.parent;
 78                     Entry<K,V> ch = p;
 79                     while (parent != null && ch == parent.right) {
 80                         ch = parent;
 81                         parent = parent.parent;
 82                     }
 83                     return parent;
 84                 }
 85             } else
 86                 return p;
 87         }
 88         return null;
 89     }
 90 
 91     //指定的key返回结点;如果没有,则返回比key小的最大的结点;
 92     //若不存在(即TreeMap中所有节点的键都比key小),就返回null” 
 93     final Entry<K,V> getFloorEntry(K key) {
 94         Entry<K,V> p = root;
 95         while (p != null) {
 96             int cmp = compare(key, p.key);
 97             if (cmp > 0) {
 98                 if (p.right != null)
 99                     p = p.right;
100                 else
101                     return p;
102             } else if (cmp < 0) {
103                 if (p.left != null) {
104                     p = p.left;
105                 } else {
106                     Entry<K,V> parent = p.parent;
107                     Entry<K,V> ch = p;
108                     while (parent != null && ch == parent.left) {
109                         ch = parent;
110                         parent = parent.parent;
111                     }
112                     return parent;
113                 }
114             } else
115                 return p;
116 
117         }
118         return null;
119     }
120 
121     //返回比key大的最小的结点;
122     //若不存在(即TreeMap中所有节点的键都比key小),就返回null” 
123     final Entry<K,V> getHigherEntry(K key) {
124         Entry<K,V> p = root;
125         while (p != null) {
126             int cmp = compare(key, p.key);
127             if (cmp < 0) {
128                 if (p.left != null)
129                     p = p.left;
130                 else
131                     return p;
132             } else {
133                 if (p.right != null) {
134                     p = p.right;
135                 } else {
136                     Entry<K,V> parent = p.parent;
137                     Entry<K,V> ch = p;
138                     while (parent != null && ch == parent.right) {
139                         ch = parent;
140                         parent = parent.parent;
141                     }
142                     return parent;
143                 }
144             }
145         }
146         return null;
147     }
148     
149     //返回比key小的最大的结点;
150     //若不存在(即TreeMap中所有节点的键都比key大),就返回null” 
151     final Entry<K,V> getLowerEntry(K key) {
152         Entry<K,V> p = root;
153         while (p != null) {
154             int cmp = compare(key, p.key);
155             if (cmp > 0) {
156                 if (p.right != null)
157                     p = p.right;
158                 else
159                     return p;
160             } else {
161                 if (p.left != null) {
162                     p = p.left;
163                 } else {
164                     Entry<K,V> parent = p.parent;
165                     Entry<K,V> ch = p;
166                     while (parent != null && ch == parent.left) {
167                         ch = parent;
168                         parent = parent.parent;
169                     }
170                     return parent;
171                 }
172             }
173         }
174         return null;
175     }
176 
177     //删除映射根据指定的key,如果存在
178     public V remove(Object key) {
179         Entry<K,V> p = getEntry(key);
180         if (p == null)
181             return null;
182 
183         V oldValue = p.value;
184         deleteEntry(p);
185         return oldValue;
186     }
187 
188     //删除所有结点
189     public void clear() {
190         modCount++;
191         size = 0;
192         root = null;
193     }
194 
195     //返回此 TreeMap 实例的浅表副本。(键和值本身不被复制。)  
196     public Object clone() {
197         TreeMap<?,?> clone;
198         try {
199             clone = (TreeMap<?,?>) super.clone();
200         } catch (CloneNotSupportedException e) {
201             throw new InternalError(e);
202         }
203 
204         // Put clone into "virgin" state (except for comparator)
205         //将clone至于原始状态(除了比较器)
206         clone.root = null;
207         clone.size = 0;
208         clone.modCount = 0;
209         clone.entrySet = null;
210         clone.navigableKeySet = null;
211         clone.descendingMap = null;
212 
213         // Initialize clone with our mappings
214         try {
215             clone.buildFromSorted(size, entrySet().iterator(), null, null);
216         } catch (java.io.IOException cannotHappen) {
217         } catch (ClassNotFoundException cannotHappen) {
218         }
219 
220         return clone;
221     }
222 
223     public Map.Entry<K,V> firstEntry() {
224         return exportEntry(getFirstEntry());
225     }
226 
227     public Map.Entry<K,V> lastEntry() {
228         return exportEntry(getLastEntry());
229     }
230 
231     //弹出第一个结点
232     public Map.Entry<K,V> pollFirstEntry() {
233         Entry<K,V> p = getFirstEntry();
234         Map.Entry<K,V> result = exportEntry(p);
235         if (p != null)
236             deleteEntry(p);
237         return result;
238     }
239     
240     //弹出最后一个结点
241     public Map.Entry<K,V> pollLastEntry() {
242         Entry<K,V> p = getLastEntry();
243         Map.Entry<K,V> result = exportEntry(p);
244         if (p != null)
245             deleteEntry(p);
246         return result;
247     }
248 
249     public Map.Entry<K,V> lowerEntry(K key) {
250         return exportEntry(getLowerEntry(key));
251     }
252 
253     public K lowerKey(K key) {
254         return keyOrNull(getLowerEntry(key));
255     }
256 
257     public Map.Entry<K,V> floorEntry(K key) {
258         return exportEntry(getFloorEntry(key));
259     }
260 
261     public K floorKey(K key) {
262         return keyOrNull(getFloorEntry(key));
263     }
264 
265     public K ceilingKey(K key) {
266         return keyOrNull(getCeilingEntry(key));
267     }
268 
269     public Map.Entry<K,V> higherEntry(K key) {
270         return exportEntry(getHigherEntry(key));
271     }
272 
273     public K higherKey(K key) {
274         return keyOrNull(getHigherEntry(key));
275     }

遍历treemap的key,value,entry:

  1  private transient EntrySet entrySet;
  2     private transient KeySet<K> navigableKeySet;
  3     private transient NavigableMap<K,V> descendingMap;
  4 
  5     //key集合
  6     public Set<K> keySet() {
  7         return navigableKeySet();
  8     }
  9 
 10     //key集合(正序:map添加key的正向顺序)
 11     public NavigableSet<K> navigableKeySet() {
 12         KeySet<K> nks = navigableKeySet;
 13         return (nks != null) ? nks : (navigableKeySet = new KeySet<>(this));
 14     }
 15 
 16     //key集合(降序:map添加key的反向顺序)
 17     public NavigableSet<K> descendingKeySet() {
 18         return descendingMap().navigableKeySet();
 19     }
 20 
 21     //映射的值的集合,顺序和key的顺应一致(正序:map添加key的正向顺序)
 22     public Collection<V> values() {
 23         Collection<V> vs = values;
 24         return (vs != null) ? vs : (values = new Values());
 25     }
 26 
 27     //映射的结点的集合,顺序和key的顺应一致(正序:map添加key的正向顺序)
 28     public Set<Map.Entry<K,V>> entrySet() {
 29         EntrySet es = entrySet;
 30         return (es != null) ? es : (entrySet = new EntrySet());
 31     }
 32 
 33     public NavigableMap<K, V> descendingMap() {
 34         NavigableMap<K, V> km = descendingMap;
 35         return (km != null) ? km :
 36             (descendingMap = new DescendingSubMap<>(this,
 37                                                     true, null, true,
 38                                                     true, null, true));
 39     }
 40 
 41     //返回此映射的部分视图,其键的范围从 fromKey 到 toKey。
 42     如果 fromKey 和 toKey 相等,则返回的映射为空,除非 fromExclusive 和 toExclusive 都为 true。
 43     返回的映射受此映射支持,因此返回映射中的更改将反映在此映射中,反之亦然。
 44     返回的映射支持此映射支持的所有可选映射操作。 
 45     如果试图在返回映射的范围之外插入一个键,或者构造一个任一端点位于其范围之外的子映射,
 46     则返回的映射将抛出 IllegalArgumentException。
 47     public NavigableMap<K,V> subMap(K fromKey, boolean fromInclusive,
 48                                     K toKey,   boolean toInclusive) {
 49         return new AscendingSubMap<>(this,
 50                                      false, fromKey, fromInclusive,
 51                                      false, toKey,   toInclusive);
 52     }
 53 
 54     //返回此映射的部分视图,其键小于(或等于,如果 inclusive 为 true)toKey。
 55     返回的映射受此映射支持,因此返回映射中的更改将反映在此映射中,反之亦然。
 56     返回的映射支持此映射支持的所有可选映射操作。 
 57     如果试图在返回映射的范围之外插入一个键,则返回的映射将抛出 IllegalArgumentException。
 58     public NavigableMap<K,V> headMap(K toKey, boolean inclusive) {
 59         return new AscendingSubMap<>(this,
 60                                      true,  null,  true,
 61                                      false, toKey, inclusive);
 62     }
 63 
 64     //同上
 65     public NavigableMap<K,V> tailMap(K fromKey, boolean inclusive) {
 66         return new AscendingSubMap<>(this,
 67                                      false, fromKey, inclusive,
 68                                      true,  null,    true);
 69     }
 70 
 71     public SortedMap<K,V> subMap(K fromKey, K toKey) {
 72         return subMap(fromKey, true, toKey, false);
 73     }
 74 
 75 
 76     public SortedMap<K,V> headMap(K toKey) {
 77         return headMap(toKey, false);
 78     }
 79 
 80     public SortedMap<K,V> tailMap(K fromKey) {
 81         return tailMap(fromKey, true);
 82     }
 83 
 84     //替换指定key,和值的值
 85     @Override
 86     public boolean replace(K key, V oldValue, V newValue) {
 87         Entry<K,V> p = getEntry(key);
 88         if (p!=null && Objects.equals(oldValue, p.value)) {
 89             p.value = newValue;
 90             return true;
 91         }
 92         return false;
 93     }
 94 
 95     //替换指定key的值
 96     @Override
 97     public V replace(K key, V value) {
 98         Entry<K,V> p = getEntry(key);
 99         if (p!=null) {
100             V oldValue = p.value;
101             p.value = value;
102             return oldValue;
103         }
104         return null;
105     }
106 
107     //类似ArrayList
108     @Override
109     public void forEach(BiConsumer<? super K, ? super V> action) {
110         Objects.requireNonNull(action);
111         int expectedModCount = modCount;
112         for (Entry<K, V> e = getFirstEntry(); e != null; e = successor(e)) {
113             action.accept(e.key, e.value);
114 
115             if (expectedModCount != modCount) {
116                 throw new ConcurrentModificationException();
117             }
118         }
119     }
replaceAll:替换所有的值
 1     @Override
 2     public void replaceAll(BiFunction<? super K, ? super V, ? extends V> function) {
 3         Objects.requireNonNull(function);
 4         int expectedModCount = modCount;
 5 
 6         for (Entry<K, V> e = getFirstEntry(); e != null; e = successor(e)) {
 7             e.value = function.apply(e.key, e.value);
 8 
 9             if (expectedModCount != modCount) {
10                 throw new ConcurrentModificationException();
11             }
12         }
13     }

demo:

 1    public static void main(String[] args) {
 2         TreeMap<String,Object> treeMap= new TreeMap();
 3         treeMap.put("1",1);
 4         treeMap.put("2",3);
 5         treeMap.put("3",3);
 6         treeMap.put("4",3);
 7         treeMap.put("5",3);
 8         
 9         BiFunction ff = new BiFunction<String, Integer, Object>() {
10             @Override
11             public Integer apply(String str,Integer v) {
12                 return 2;
13             }
14         };
15         treeMap.replaceAll(ff);
16         System.out.println(treeMap);
17     }

结果:

1 {1=2, 2=2, 3=2, 4=2, 5=2}

TreeMap有Values、EntrySet、KeySet、PrivateEntryIterator、EntryIterator、ValueIterator、KeyIterator、DescendingKeyIterator、NavigableSubMap、AscendingSubMap、DescendingSubMap、SubMap、Entry共十三个内部类。可以参考这篇博客:https://blog.csdn.net/jzhf2012/article/details/8540713

原文地址:https://www.cnblogs.com/sqy123/p/9376195.html