力扣—one plus(加一) python实现

题目描述:

中文:

给定一个由整数组成的非空数组所表示的非负整数,在该数的基础上加一。

最高位数字存放在数组的首位, 数组中每个元素只存储单个数字。

你可以假设除了整数 0 之外,这个整数不会以零开头。

英文:

Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.

You may assume the integer does not contain any leading zero, except the number 0 itself.

class Solution(object):
    def plusOne(self, digits):
        """
        :type digits: List[int]
        :rtype: List[int]
        """
        length=len(digits)
        i=length-1
        while(i>=0):
            if i==0:
                if (digits[i]+1)>9:
                    digits[i]=0
                    result=[1]
                    result.extend(digits)
                    return result
            if (digits[i]+1)<=9:
                digits[i]+=1
                return digits
            else:
                digits[i]=0
                i-=1
        return digits

题目来源:力扣

原文地址:https://www.cnblogs.com/spp666/p/11594622.html