A Read–Eval–Print Loop (REPL), also known as an interactive toplevel or language shell, is a simple, interactive computer programming environment that takes single user inputs (i.e. single expressions), evaluates them, and returns the result to the user; a program written in a REPL environment is executed piecewise. The term is most usually used to refer to programming interfaces similar to the classic Lisp machine interactive environment. Common examples include command line shells and similar environments for programming languages, and is particularly characteristic of scripting languages.[1]
In a REPL, the user enters one or more expressions (rather than an entire compilation unit) and the REPL evaluates them and displays the results. The name read–eval–print loop comes from the names of the Lisp primitive functions which implement this functionality:
The read function accepts an expression from the user, and parses it into a data structure in memory. For instance, the user may enter the s-expression (+ 1 2 3), which is parsed into a linked list containing four data elements.
The eval function takes this internal data structure and evaluates it. In Lisp, evaluating an s-expression beginning with the name of a function means calling that function on the arguments that make up the rest of the expression. So the function + is called on the arguments 1 2 3, yielding the result 6.
The print function takes the result yielded by eval, and prints it out to the user. If it is a complex expression, it may be pretty-printed to make it easier to understand. In this example, though, the number 6 does not need much formatting to print.
The development environment then returns to the read state, creating a loop, which terminates when the program is closed.
REPL — 交互式解释器环境。
R(read)、E(evaluate)、P(print)、L(loop)
输入值，交互式解释器会读取输入内容并对它求值，再返回结果，并重复此过程。
1 简介
近期对Scala比较感兴趣，买了本《快学Scala》,感觉不错。比《Programming Scala:Tackle Multi-Core Complexity on the Java Virtual Machine》好很多。 是本不错的入门书。而且每个章节都设置了难度级别，每章有习题，可以巩固Scala语法。
本文的目的就是针对这些习题进行解答
2 基础
这个。。。。直接操作一遍就有结果了.此题不知是翻译的问题，还是原题的问题，在Scala REPL中需要按3. 然后按Tab才会提示。 直接按3加Tab是没有提示的。下面是结果
!= ## % & * + - / < << <= == > >= >> >>> ^ asInstanceOf equals getClass hashCode isInstanceOf toByte toChar toDouble toFloat toInt toLong toShort toString unary_+ unary_- unary_~ |
列出的方法并不全，需要查询全部方法还是需要到Scaladoc中的Int,Double,RichInt,RichDouble等类中去查看。
2.2 在Scala REPL中，计算3的平方根,然后再对该值求平方。现在，这个结果与3相差多少？(提示:res变量是你的朋友)
依次进行计算即可
scala> scala.math.sqrt(3) warning: there were 1 deprecation warnings; re-run with -deprecation for details res5: Double = 1.7320508075688772 scala> res5*res5 res6: Double = 2.9999999999999996 scala> 3 - res6 res7: Double = 4.440892098500626E-16
或
2.3 res变量是val还是var?
val是不可变的，而var是可变的，只需要给res变量重新赋值就可以检测res是val还是var了
scala> res9 = 3
<console>:8: error: reassignment to val
res9 = 3
^
2.4 Scala允许你用数字去乘字符串—去REPL中试一下"crazy"*3。这个操作做什么？在Scaladoc中如何找到这个操作?
scala> "crazy"*3 res11: String = crazycrazycrazy
从代码可以推断,*是"crazy"这个字符串所具有的方法，但是Java中的String可没这个方法，很明显。此方法在StringOps中。
2.5 10 max 2的含义是什么？max方法定义在哪个类中？
直接在REPL中执行
scala> 10 max 2 res0: Int = 10 scala> 7 max 8 res1: Int = 8 scala> 0 max 0 res2: Int = 0
可以看出,此方法返回两个数字中较大的那个。此方法Java中不存在，所以在RichInt中。
2.6 用BigInt计算2的1024次方
简单的API调用
scala> BigInt(2).pow(1024) res4: scala.math.BigInt = 1797693134862315907729305190789024733617976978942306572734300811577326758055009631327084773224 075360211201138798713933576587897688144166224928474306394741243777678934248654852763022196012460941194530829520850057688 38150682342462881473913110540827237163350510684586298239947245938479716304835356329624224137216
2.7 为了在使用probablePrime(100,Random)获取随机素数时不在probablePrime和Radom之前使用任何限定符，你需要引入什么？
so easy. import需要的包啊。Random在scala.util中，而probablePrime是BigInt中的方法，引入即可
import scala.math.BigInt._ import scala.util.Random probablePrime(3,Random)
2.8 创建随机文件的方式之一是生成一个随机的BigInt，然后将它转换成三十六进制，输出类似"qsnvbevtomcj38o06kul"这样的字符串。查阅Scaladoc，找到在Scala中实现该逻辑的办法。
到BigInt中查找方法。
scala> scala.math.BigInt(scala.util.Random.nextInt).toString(36) res21: String = utydx
2.9 在Scala中如何获取字符串的首字符和尾字符？
//获取首字符 "Hello"(0) "Hello".take(1) //获取尾字符 "Hello".reverse(0) "Hello".takeRight(1)
2.10 take,drop,takeRight和dropRight这些字符串函数是做什么用的？和substring相比，他们的优点和缺点都是哪些？
查询API即可 take是从字符串首开始获取字符串,drop是从字符串首开始去除字符串。 takeRight和dropRight是从字符串尾开始操作。 这四个方法都是单方向的。 如果我想要字符串中间的子字符串，那么需要同时调用drop和dropRight，或者使用substring