杭电1253--胜利的大逃亡(Bfs)

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1253

题意: 迷宫问题,  三维数组, 数据范围较大, Bfs较优。  PS-----> 堕落了几天, 是时候奋斗了,fighting!! 

//ac码:1669ms;
#include <queue>
#include <cstdio>
#include <cstring>
#include <iostream>
using namespace std;
int map[55][55][55]; int ac[6][3] = {0, 0, 1, 0, 0, -1, 0, 1, 0, 0, -1, 0, 1, 0, 0, -1, 0, 0};
struct Maze
{
    int x, y, z, step;
}r, s, t;
int a, b, c, T;
int Bfs(int x, int y, int z)
{
    queue<Maze> Q;
    r.x = x; r.y = y; r.z = z; r.step = 0;
    Q.push(r);
    map[x][y][z] = 1;
    while(!Q.empty())
    {
        s = Q.front(); Q.pop();
        for(int i = 0; i < 6; i++)
        { 
            t.x = s.x + ac[i][0]; 
            t.y = s.y + ac[i][1];
            t.z = s.z + ac[i][2];
            t.step = s.step + 1;
            if(t.x >= 0 && t.x < a && t.y >= 0 && t.y < b && t.z >= 0 && t.z < c && map[t.x][t.y][t.z] == 0)
            {
                if(t.x == a - 1 && t.y == b - 1 && t.z == c - 1 && t.step <= T)            
                    return t.step;
                else
                {
                    map[t.x][t.y][t.z] = 1;
                    Q.push(t);
                }
            } 
        }
    } 
    return -1;
} 
int main()
{
    int k;
    scanf("%d", &k);
    while(k--)
    {
        scanf("%d %d %d %d", &a, &b, &c, &T);
        for(int i = 0; i < a; i++)
            for(int j = 0; j < b; j++)
                for(int k = 0; k < c; k++)
                    //cin >> map[i][j][k];
                    scanf("%d", &map[i][j][k]);
        int ans = Bfs(0, 0, 0); 
        printf("%d
", ans);
    }
    return 0;
}
原文地址:https://www.cnblogs.com/soTired/p/4775436.html