杭电2952--Counting Sheep (Dfs)

题目:http://acm.hdu.edu.cn/showproblem.php?pid=2952

水一道Dfs; 求羊群数量, 暴力标记跑一遍就OK.

#include <cstdio>
#include <cstring>
#include <iostream>
using namespace std;
char map[101][101]; int ac[4][2] = {0, 1, 0, -1, -1, 0, 1, 0};
int n, m;
void Dfs(int x, int y)
{
    int nx, ny;
    map[x][y] = '.';
    for(int i = 0; i < 4; i++)
    {
        nx = x + ac[i][0];
        ny = y + ac[i][1];
        if(nx >= 0 && ny >= 0 && nx < n && ny < m && map[nx][ny] != '.')
            Dfs(nx, ny); 
    }
}
int main()
{
    int t;
    scanf("%d", &t);
    while(t--)
    {
        int cnt = 0;
        scanf("%d %d", &n, &m);
        for(int i = 0; i < n; i++)
            cin >> map[i];
        for(int i = 0; i < n; i++)
            for(int j = 0; j < m; j++)
            {
                if(map[i][j] == '#')
                {
                    Dfs(i, j);
                    cnt++;
                }
            }
        printf("%d
", cnt); 
    }
    return 0; 
} 
原文地址:https://www.cnblogs.com/soTired/p/4763355.html