杭电2133--What day is it

What day is it

Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4261 Accepted Submission(s): 1252

Problem Description

Today is Saturday, 17th Nov,2007. Now, if i tell you a date, can you tell me what day it is ?

Input

There are multiply cases.
One line is one case.
There are three integers, year(0<year<10000), month(0<=month<13), day(0<=day<32).

Output

Output one line.
if the date is illegal, you should output "illegal". Or, you should output what day it is.

Sample Input

2007 11 17

Sample Output

Saturday

Author

LGX

Source

HDU 2007-11 Programming Contest_WarmUp

//蔡勒公式坑！

 1 #include <stdio.h>
 2 char str[20][20]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"} ;
 3 int num[13] = {0,31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31} ;     //这边坑！ 
 4 int shu[13] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31} ;
 5 
 6 int judge(int year)
 7 {
 8     if(year%4 == 0 && year%100!=0 || year%400 == 0)
 9     return 1 ;
10     else
11     return 0;
12 }
13 
14 int main()
15 {
16     int year, month, day, p ;
17     while(~scanf("%d %d %d",&year, &month, &day))
18     {
19         int t = judge(year) ;                                          
20         if(t == 0)                                                  //这边坑！ 
21         {
22         
23             if(day > num[month] || month == 0 || day == 0)
24             {
25                 printf("illegal
") ;
26                 continue ;
27             }
28         }
29         else                                                       //这边坑； 
30         {
31             //num[2] += 1 ;
32             if(day > shu[month] || month == 0 || day == 0)
33             {
34                 printf("illegal
") ;
35                 continue ;
36             }
37         }                                                            
38 
39         int i, sum=0 ;
40          for(i=1; i<year; i++)
41         {
42             if(judge(i) == 1)
43             sum += 366 ;
44             else
45             sum += 365 ;
46             sum=sum%7 ;
47         }
48         
49         sum += day ;
50         for(i=1; i<month; i++)
51         {
52             if(t == 1)
53             sum+= shu[i] ;
54             else
55             sum+=num[i] ;
56             sum = sum % 7 ;
57         }
58         sum = sum%7 ;
59         printf("%s
" ,str[sum]) ;
60     }
61     return 0 ;
62 }

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