Guava中集合类的简单实用

1.Lists

 1 //Lists
 2 System.out.println("### Lists ###");
 3 ArrayList<String> arrayList = Lists.newArrayList();
 4 arrayList.add("A");
 5 arrayList.add("B");
 6 arrayList.add("C");
 7 System.out.println(arrayList);
 8 
 9 LinkedList<String> linkedList = Lists.newLinkedList();
10 linkedList.add("A");
11 linkedList.add("B");
12 linkedList.add("C");
13 System.out.println(linkedList);
14 
15 System.out.println(Lists.reverse(arrayList));   //翻转集合元素的顺序
16 System.out.println(Lists.reverse(linkedList));
17 
18 System.out.println(Lists.partition(arrayList, 2)); //一个集合内再分成n个子集合

2.Sets

//Sets
System.out.println("### Sets ###");
HashSet<String> set1 = Sets.newHashSet();
set1.add("A");
set1.add("B");
set1.add("C");

LinkedHashSet<String> set2 = Sets.newLinkedHashSet();
set2.add("B");
set2.add("C");
set2.add("D");
set2.add("E");

//Sets.newTreeSet();
//Sets.newConcurrentHashSet();

System.out.println(Sets.union(set1, set2)); //返回两个集合的并集  >> [A, B, C, D, E]
System.out.println(Sets.difference(set1, set2)); //返回set1中不存在于set2的元素集合  >> [A]
System.out.println(Sets.intersection(set1, set2)); //返回两个集合的交集  >> [B, C]

Set<String> resultSet = Sets.filter(set2, new Predicate<String>() {
    @Override
    public boolean apply(String value) {
        return !"D".equals(value); //过滤掉值为D的元素  >> [B, C, E]
    }
});
System.out.println(resultSet);

3.Maps

//Maps
System.out.println("### Maps ###");
Maps.newHashMap();
Maps.newLinkedHashMap();
Maps.newTreeMap();
Maps.newConcurrentMap();

4.Collections

//Collections2
System.out.println("### Collections2 ###");
Collection<String> linkedList2 = Collections2.filter(linkedList, new Predicate<String>() {
    @Override
    public boolean apply(String value) {
        return !"B".equals(value); //过滤器:过滤掉值为B的元素  >> [A, C]
    }
});
System.out.println(linkedList2);

Collection<String> linkedList3 = Collections2.transform(linkedList, new Function<String, String>() {
    @Override
    public String apply(String value) {
        return value + "_"; //转换器:元素值做特殊处理后返回  >> [A_, B_, C_]
    }
});
System.out.println(linkedList3);
原文地址:https://www.cnblogs.com/skyke/p/6015706.html