指针数组什么的真麻烦

#include<stdio.h>
#include<string.h>
int main(){

	printf("char arg1[]={"one1"}
");
	char arg1[]={"one1"};
	printf("%s

",arg1);

	printf("char *arg2={"one2"}:
");
	char *arg2={"one2"};
	printf("%s

",arg2);

	printf("char arg3[][10]={"one3","two3"}:
");
	char arg3[][10]={"one3","two3"};
	printf("%s
%s

",arg3[0],arg3[1]);

	printf("char *arg4[]={"one4","two4"}:
");
	char *arg4[]={"one4","two4"};
	printf("%s
%s

",arg4[0],arg4[1]);

	printf("char **ar=arg4:
");
	char **ar=arg4;
	printf("%s
%s

",*ar,*(ar+1));

	putchar(10);
	return 0;
}

原文地址:https://www.cnblogs.com/sjw1357/p/3864015.html