get 发送ajax请求

上demo小案例

<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8">
    <title></title>
</head>
<body>
    <input type="" name="" value="" id='nameTest'>
    <input type="button"  value="发送ajax请求" id='btnAjax'> 
</body>
</html>
<script type="type/javascript">
	document.querySelector("#btnAjax").onclick=function(){
	//创建ajax
	var ajax=new XMLHttpRequest();
	//设置ajax 的url
	//获取标签的值
	var username=document.querySelector("#nameTest").value;
	ajax.open('get','ajax.php?name='+username);
		
	ajax.send();
	
	ajax.onreadystatechange=function(){
		if(ajax.readyState==4 && ajax.status==200){
			console.log(ajax.responseText);
		}
	} 	
		
}
</script>

调用PHP文件路径

<?php
	echo $_GET['name'].'这道菜好吃'
?>

  

  

原文地址:https://www.cnblogs.com/sj1988/p/6515205.html