二维数组的连续子数组的最大和

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public static int[][] arrSum(int arr[][]){
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    int m = arr.length;
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    int n = arr[0].length;
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    int p[][] = new int[m+1][n+1];
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    p[0][0] = arr[0][0];
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    for(int i=0; i<=m; i++) p[i][0] = 0;
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    for(int i=0; i<=n; i++) p[0][i] = 0;
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    for(int i=1; i<=m; i++){
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        for(int j=1; j<=n; j++){
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            p[i][j] = p[i-1][j] + p[i][j-1] + arr[i-1][j-1] - p[i-1][j-1];
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        }
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    }
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    return p;
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}
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//遍历所有二维数组的矩形区域
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static int  maxArrSum(int arr[][]){
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    int m = arr.length;
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    int n = arr[0].length;
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    int p[][] = arrSum(arr);
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    int ans = Integer.MIN_VALUE;
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    for(int i=1; i<=m; i++){
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        for(int j=1; j<=n; j++){
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            for(int endi=i; endi <=m; endi++){
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                for(int endj=j; endj<=n; endj++){
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                    int sum = p[endi][endj] - p[i-1][endj] - p[endi][j-1] + p[i-1][j-1];
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                    if(ans < sum) ans = sum;
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                }
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            }
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        }
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    }
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    return ans;
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}
原文地址:https://www.cnblogs.com/silianbo/p/4842662.html