24、合并两个有序链表

24、合并两个有序链表

将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。

示例:

输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4

答案解析:

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
    public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
        if (l1 == null){
            return l2;
        }
        if (l2 == null){
            return l1;
        }
        ListNode head = new ListNode(0);
        ListNode temp = head;
        while (l1 != null && l2 != null){
            if (l1.val > l2.val){
                temp.next = l2;
                l2 = l2.next;
            }else {
                temp.next = l1;
                l1 = l1.next;
            }
            temp = temp.next;
        }
        if (l1 != null){
            temp.next = l1;
        }
        if (l2 != null){
            temp.next = l2;
        }
        return head.next;
    }
}
原文地址:https://www.cnblogs.com/sikaozhifu/p/10764885.html