简单的访客IP获取类-IPHelper.cs

 1 public class IPHelper
 2 {
 3     public static string GetVisitorsIPAddress()
 4     {
 5         string result = String.Empty;
 6  
 7         result = System.Web.HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
 8  
 9         // 如果使用代理，获取真实IP
10         if (result != null && result.IndexOf(".") == -1)    //没有“.”肯定是非IPv4格式
11             result = null;
12         else if (result != null)
13         {
14             if (result.IndexOf(",") != -1)
15             {
16                 //有“,”，估计多个代理。取第一个不是内网的IP。
17                 result = result.Replace(" ", "").Replace("'", "");
18                 string[] temparyip = result.Split(",;".ToCharArray());
19                 for (int i = 0; i < temparyip.Length; i++)
20                 {
21                     if (IsIPAddress(temparyip[i])
22                         && temparyip[i].Substring(0, 3) != "10."
23                         && temparyip[i].Substring(0, 7) != "192.168"
24                         && temparyip[i].Substring(0, 7) != "172.16.")
25                     {
26                         return temparyip[i];    //找到不是内网的地址
27                     }
28                 }
29             }
30             else if (IsIPAddress(result)) //代理即是IP格式
31                 return result;
32             else
33                 result = null;    //代理中的内容 非IP，取IP
34         }
35         if (null == result || result == String.Empty)
36             result = System.Web.HttpContext.Current.Request.ServerVariables["REMOTE_ADDR"];
37  
38         if (result == null || result == String.Empty)
39             result = System.Web.HttpContext.Current.Request.UserHostAddress;
40  
41         return result;
42     }
43  
44     /// <summary>
45     /// 判断是否是IP地址格式 0.0.0.0
46     /// </summary>
47     /// <param name="str1">待判断的IP地址</param>
48     /// <returns>true or false</returns>
49     private static bool IsIPAddress(string str1)
50     {
51         if (str1 == null || str1 == string.Empty || str1.Length < 7 || str1.Length > 15) return false;
52  
53         string regformat = @"^d{1,3}[.]d{1,3}[.]d{1,3}[.]d{1,3}$";
54  
55         Regex regex = new Regex(regformat, RegexOptions.IgnoreCase);
56         return regex.IsMatch(str1);
57     }
58 }