将一维数组中元素随机打乱排序

从原List中每次随机取一项，添加到新的List中，并在原List中删除。这样重复，直到原List为空为止。

public static List<T> GetRandomList<T>(List<T> inputList)
{
    //Copy to a array
    T[] copyArray = new T[inputList.Count];
    inputList.CopyTo(copyArray);

    //Add range
    List<T> copyList = new List<T>();
    copyList.AddRange(copyArray);

    //Set outputList and random
    List<T> outputList = new List<T>();
    Random rd = new Random(DateTime.Now.Millisecond);

    while (copyList.Count > 0)
    {
        //Select an index and item
        int rdIndex = rd.Next(0, copyList.Count - 1);
        T remove = copyList[rdIndex];

        //remove it from copyList and add it to output
        copyList.Remove(remove);
        outputList.Add(remove);
    }
    return outputList;
}

用linq

List<T> l = new List<T>();
l = l.Select(a => new { a, newID = Guid.NewGuid() }).OrderBy(b => b.newID).Select(c=>c.a).ToList();

得到随机数的方法

Random r=new Random();

int n1=r.Next(); //返回非负随机整数

Response.Write(n1+" ");

int n2=r.Next(10); //返回一个小于所指定最大值（10）的非负随机整数

Response.Write(n2+" ");

int n3=r.Next()%10; //返回一人小于所指定最大值（10）的非负随机整数

Response.Write(n3+" ");

int n4=r.Next(1,20); //返回一个指定范围（1-20）内的随机整数

Response.Write(n4+" ");

double d5=r.NextDouble(); //得到一个介于0.0-1.0之间的随机整数

Response.Write(d5+" ");