翻转整数

int ReverseInterage(int Num)
    {
        long long tmp = 0;
        for (; Num; Num /= 10)
            tmp = tmp * 10 + Num % 10;
        return  (tmp <= INT_MAX && tmp >= INT_MIN) ? tmp : 0;
    }
整数的翻转
原文地址:https://www.cnblogs.com/shihaochangeworld/p/5674808.html