poj1942(组合数模板)

http://poj.org/problem?id=1942

View Code
 1 #include<stdio.h>
 2 int main()
 3 {
 4     __int64 s,n,m,i,j,k;
 5     while(scanf("%I64d%I64d", &n,&m)!=EOF)
 6     {
 7         if(n==0&&m==0)
 8             break;
 9         s = 1;
10         if(n>m)
11             k = m;
12         else
13             k = n;
14         n+=m;
15         for(j = 1 ; j <= k ; j++,n--)
16         {
17             s =s *n/j;
18         }
19         printf("%I64d\n",s);
20     }
21     return 0;
22 }
View Code
 1 __int64 C(__int64 m, __int64 n){
 2     if(m > n - m) m = n - m;
 3     __int64 ans = 1, cou = m;
 4     while(cou --){
 5         ans *= n --;
 6         while(ans % m == 0 && m > 1)
 7             ans /= m --;
 8     }
 9     return ans;
10 }

 递推模板

View Code
1 void cn()
2 {
3     for(int i=0;i<=32;i++)
4         for(int j=0;j<=i;j++)
5             if(!j || i==j)
6                 c[i][j]=1;
7             else
8                 c[i][j]=c[i-1][j-1]+c[i-1][j];
9 }
原文地址:https://www.cnblogs.com/shangyu/p/2617371.html