【leetcode】1662. Check If Two String Arrays are Equivalent

题目如下:

Given two string arrays word1 and word2, return true if the two arrays represent the same string, and false otherwise.

A string is represented by an array if the array elements concatenated in order forms the string.

Example 1:

Input: word1 = ["ab", "c"], word2 = ["a", "bc"]
Output: true
Explanation:
word1 represents string "ab" + "c" -> "abc"
word2 represents string "a" + "bc" -> "abc"
The strings are the same, so return true.

Example 2:

Input: word1 = ["a", "cb"], word2 = ["ab", "c"]
Output: false

Example 3:

Input: word1  = ["abc", "d", "defg"], word2 = ["abcddefg"]
Output: true

Constraints:

  • 1 <= word1.length, word2.length <= 103
  • 1 <= word1[i].length, word2[i].length <= 103
  • 1 <= sum(word1[i].length), sum(word2[i].length) <= 103
  • word1[i] and word2[i] consist of lowercase letters.

解题思路:有什么可说的呢?

代码如下:

class Solution(object):
    def arrayStringsAreEqual(self, word1, word2):
        """
        :type word1: List[str]
        :type word2: List[str]
        :rtype: bool
        """
        return ''.join(word1) == ''.join(word2)
原文地址:https://www.cnblogs.com/seyjs/p/14931525.html